CODEWITHSUNDEEP
linuxbashshell
MMA
MMA

Reputation: 458

List files of directory into array without file extension

I have files like:

abc.json
xyz.json
pdf.json

I would like to get the result like this without "json" extension:

somearray=(abc, xyz, pdf)

Upvotes: 1

Views: 1490

Answers (2)

Benjamin W.
Benjamin W.

Reputation: 52211

You can get your files into an array with globbing, then remove the extensions with parameter expansion:

$ arr=(*.json)
$ declare -p arr
declare -a arr='([0]="abc.json" [1]="pdf.json" [2]="xyz.json")'
$ arr=("${arr[@]%.json}")
$ declare -p arr
declare -a arr='([0]="abc" [1]="pdf" [2]="xyz")'

Upvotes: 4

codeforester
codeforester

Reputation: 43039

You can do it simply with this:

some_array=( $(ls | sed 's/.json$//') )

Or, if you are only looking for .json files, then:

some_array=( $(ls | grep '.json$' | sed 's/.json$//') )

The method above is not safe if you have any files that have white space or wildcard (*) in them.

If you are using Bash, then you can use parameter expansion to take the extension out. And this approach is more robust than the earlier ones - it handles files with white spaces or wildcard gracefully:

declare -a some_array
for file in *.json; do
  some_array+=( "${file%.json}" )
done

See these posts:

Upvotes: 2

Related Questions