Reputation: 2101
I have the following JSON and I want to keep the array in the same format but only include objects with type "ar"
. How can I filter this JSON with JavaScript to only include the types I need?
[{"time":"2016-07-26 09:02:27","type":"aa"},
{"time":"2016-04-21 20:35:07","type":"ae"},
{"time":"2016-08-20 03:31:57","type":"ar"},
{"time":"2017-01-19 22:58:06","type":"ae"},
{"time":"2016-08-28 10:19:27","type":"ae"},
{"time":"2016-12-06 10:36:22","type":"ar"},
{"time":"2016-07-09 12:14:03","type":"ar"},
{"time":"2016-10-25 05:05:37","type":"ae"},
{"time":"2016-06-05 07:57:18","type":"ae"},
{"time":"2016-10-08 22:03:03","type":"aa"},
{"time":"2016-08-13 21:27:37","type":"ae"},
{"time":"2016-04-09 07:36:16","type":"ar"},
{"time":"2016-12-30 17:20:08","type":"aa"},
{"time":"2016-03-11 17:31:46","type":"aa"},
{"time":"2016-05-04 14:08:25","type":"ar"},
{"time":"2016-11-29 05:21:02","type":"ar"},
{"time":"2016-03-08 05:46:01","type":"ar"},
]
Upvotes: 47
Views: 177308
Reputation: 48437
You should use filter
method.
The filter()
method creates a new array
with all elements that pass the test implemented by the provided function.
Provided function is a callback
which is applied to each element of the array.
var arr = [{"time":"2016-07-26 09:02:27","type":"aa"}, {"time":"2016-04-21 20:35:07","type":"ae"}, {"time":"2016-08-20 03:31:57","type":"ar"}, {"time":"2017-01-19 22:58:06","type":"ae"}, {"time":"2016-08-28 10:19:27","type":"ae"}, {"time":"2016-12-06 10:36:22","type":"ar"}, {"time":"2016-07-09 12:14:03","type":"ar"}, {"time":"2016-10-25 05:05:37","type":"ae"}, {"time":"2016-06-05 07:57:18","type":"ae"}, {"time":"2016-10-08 22:03:03","type":"aa"}, {"time":"2016-08-13 21:27:37","type":"ae"}, {"time":"2016-04-09 07:36:16","type":"ar"}, {"time":"2016-12-30 17:20:08","type":"aa"}, {"time":"2016-03-11 17:31:46","type":"aa"}, {"time":"2016-05-04 14:08:25","type":"ar"}, {"time":"2016-11-29 05:21:02","type":"ar"}, {"time":"2016-03-08 05:46:01","type":"ar"}, ];
console.log(arr.filter(function(item){
return item.type == "ar";
}));
Also, you can use a shorter
way with arrow
functions:
var filtered = arr.filter(a => a.type == "ar");
Upvotes: 72
Reputation: 67525
You could use filter
function. Check browser support first:
var result = a.filter(function(v){
return v.type==='ar';
})
Hope this helps.
var list = [
{"time":"2016-07-26 09:02:27","type":"aa"},
{"time":"2016-04-21 20:35:07","type":"ae"},
{"time":"2016-08-20 03:31:57","type":"ar"},
{"time":"2017-01-19 22:58:06","type":"ae"},
{"time":"2016-08-28 10:19:27","type":"ae"},
{"time":"2016-12-06 10:36:22","type":"ar"},
{"time":"2016-07-09 12:14:03","type":"ar"},
{"time":"2016-10-25 05:05:37","type":"ae"},
{"time":"2016-06-05 07:57:18","type":"ae"},
{"time":"2016-10-08 22:03:03","type":"aa"},
{"time":"2016-08-13 21:27:37","type":"ae"},
{"time":"2016-04-09 07:36:16","type":"ar"},
{"time":"2016-12-30 17:20:08","type":"aa"},
{"time":"2016-03-11 17:31:46","type":"aa"},
{"time":"2016-05-04 14:08:25","type":"ar"},
{"time":"2016-11-29 05:21:02","type":"ar"},
{"time":"2016-03-08 05:4601","type":"ar"},
];
var result = list.filter(function(obj, index){
return obj.type==='ar';
})
console.log(result);
Upvotes: 2
Reputation: 4232
Not as clean as the answer above, but will still do the job
var list = [{"time":"2016-07-26 09:02:27","type":"aa"},
{"time":"2016-04-21 20:35:07","type":"ae"},
{"time":"2016-08-20 03:31:57","type":"ar"},
{"time":"2017-01-19 22:58:06","type":"ae"},
{"time":"2016-08-28 10:19:27","type":"ae"},
{"time":"2016-12-06 10:36:22","type":"ar"},
{"time":"2016-07-09 12:14:03","type":"ar"},
{"time":"2016-10-25 05:05:37","type":"ae"},
{"time":"2016-06-05 07:57:18","type":"ae"},
{"time":"2016-10-08 22:03:03","type":"aa"},
{"time":"2016-08-13 21:27:37","type":"ae"},
{"time":"2016-04-09 07:36:16","type":"ar"},
{"time":"2016-12-30 17:20:08","type":"aa"},
{"time":"2016-03-11 17:31:46","type":"aa"},
{"time":"2016-05-04 14:08:25","type":"ar"},
{"time":"2016-11-29 05:21:02","type":"ar"},
{"time":"2016-03-08 05:46:01","type":"ar"},
]
var newList = [];
for (var i = 0; i < list.length; i++) {
if (list[i].type === 'ar') {
newList.push(list[i]);
}
}
console.log(newList);
Upvotes: 0
Reputation: 9928
Using filter
method you can filter the array to return only those elements which match a particular condition data.filter((x)=>x.type === "ar");
The filter
method creates a new array with all elements that will pass the condition x.type === "ar"
var data =[{"time":"2016-07-26 09:02:27","type":"aa"},
{"time":"2016-04-21 20:35:07","type":"ae"},
{"time":"2016-08-20 03:31:57","type":"ar"},
{"time":"2017-01-19 22:58:06","type":"ae"},
{"time":"2016-08-28 10:19:27","type":"ae"},
{"time":"2016-12-06 10:36:22","type":"ar"},
{"time":"2016-07-09 12:14:03","type":"ar"},
{"time":"2016-10-25 05:05:37","type":"ae"},
{"time":"2016-06-05 07:57:18","type":"ae"},
{"time":"2016-10-08 22:03:03","type":"aa"},
{"time":"2016-08-13 21:27:37","type":"ae"},
{"time":"2016-04-09 07:36:16","type":"ar"},
{"time":"2016-12-30 17:20:08","type":"aa"},
{"time":"2016-03-11 17:31:46","type":"aa"},
{"time":"2016-05-04 14:08:25","type":"ar"},
{"time":"2016-11-29 05:21:02","type":"ar"},
{"time":"2016-03-08 05:46:01","type":"ar"},
];
var result = data.filter((x)=>x.type === "ar");
console.log(result);
Upvotes: 4