CODEWITHSUNDEEP
python
Shaked
Shaked

Reputation: 185

List comprehension produces wrong values

I have a list of many values which i need to get rid of some values. I want to get from all elements that don't fit. I need to have elements only in range(x, y). I tried this: K = [v > x and v < y for v in L] However I get a list of True and False values... How can I achieve that ?

Example:

L = [4, 5, 7]
range = [4, 6]
K = [5]

Upvotes: 1

Views: 75

Answers (3)

Jarvis
Jarvis

Reputation: 8564

The expression a > b is a boolean expression, which can be True or False, and moreover, you are taking the logical AND of two boolean expressions, and thats why you get a list of True and False. If want to get the values in a given range, do this :

K = [i for i in L if (i > range[0] and i < range[1])]

Upvotes: 1

Chris_Rands
Chris_Rands

Reputation: 41168

The reason you get booleans is you're returning the result of the comparison rather than the value. Also Python chains the comparisons so you don't need to use and:

K = [v for v in L if x < v < y]

Upvotes: 5

Tony Tannous
Tony Tannous

Reputation: 14856

Option 1:

`K = [v for v in L if v > num1 and v < num2]`

Option 2:

`K = filter(lambda x: x > num1 and x < num2, L)`

You should have added the if otherwise you will get the boolean results...

Upvotes: 2

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