CODEWITHSUNDEEP
pythonbashsortinglslistdir
Trigremm
Trigremm

Reputation: 71

modify bash ls command to sort by ending characters

I have a directory with a lot of log files like sample_step1[_step2[_step3]].log

to check complition of each step I run python ls_end.py, which is 

from os import listdir
from os.path import getsize, isfile

def end_sort(s): return s[::-1]


files = [i for i in listdir('.') if isfile(i) and not i.startswith('.')]
for i in sorted(files, key=end_sort):
    print("{:10.2f}\t{}".format(getsize(i)/1024, i))

is there any alternative in bash to sort files in directory from the ending ?

Upvotes: 1

Views: 186

Answers (2)

rici
rici

Reputation: 241881

That seems like a highly unorthodox sorting method, but you could do it easily enough in bash if you have the util-linux package installed, which includes the rev utility:

ls | rev | sort | rev

Another possibility, which is a slightly more conventional sort, would be:

ls | sort -t_ -k4 -k3,3 -k2,2

That will sort each step field in normal order, but will place files with missing step2 and step3 in a different order, which may or may not be what you're looking for.

Upvotes: 2

Gene
Gene

Reputation: 46990

How about

ls | rev | sort | rev

?

Upvotes: 1

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