CODEWITHSUNDEEP
assemblyx86-16emu8086
wendellex
wendellex

Reputation: 11

Why print num is always zero in emu8086

When I input numbers on my 2 variables I think it doesn't read it, so mov has 0 value.

No problem compiling.

Here's my code:

include 'emu8086.inc'
org 100h

define_print_string
define_scan_num             
define_print_num            
define_print_num_uns
define_clear_screen

.model small
.data

;data
a db "oops",0
b db 0dh,0ah,"enter first number: ",0
c db 0dh,0ah,"the sum is :",0
d db 0dh,0ah,"Press 1 if adiition",0
e db 0dh,0ah,"Press 2 if subtraction",0
f db 0dh,0ah,"the diffirence is: ",0
g db 0dh,0ah,"enter second number: ",0
h db 0dh,0ah,"",0
num1 dw 0
num2 dw 0
result dw 0

;code
.code

start:
lea si,a
call print_string
lea si,d
call print_string
lea si,e
call print_string
mov ah,1
int 21h
cmp al,'1'
je addi
cmp al,'2'
je subt
cmp al,'?'
je start

;input number 1
proc enter1
lea si,b
call print_string
call scan_num
mov ax,num1
ret
endp enter1

;input number 2
proc enter2
lea si,g
call print_string
call scan_num
mov bx,num2
ret
endp enter2    

addi:
call enter1
call enter2
add ax,bx
lea si,h
call print_string
lea si,c
call print_string
call print_num

subt:

end1:

end

screenshot

Upvotes: 0

Views: 715

Answers (1)

Sep Roland
Sep Roland

Reputation: 39676

call scan_num
mov ax,num1

The scan_num macro leaves its result in the AX register. Therefore you need to store AX in the num1 variable using mov num1, ax.
The same applies to entering the 2nd number.

cmp al,'?'
je start
;input number 1
proc enter1

Consider what happens when the input is neither "1", nor "2", nor "?".
The code will fall through in the enter1 procedure!
Better write:

jmp  start
;input number 1
proc enter1

You should calculate your sum as late as possible if you solely keep it in a register. You didn't use the result variable.

lea si,c
call print_string
mov  ax, num1
add  ax, num2
call print_num

Upvotes: 1

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