CODEWITHSUNDEEP
lambdajava-8sumfieldaggregate
Ashwani Kumar
Ashwani Kumar

Reputation: 663

Aggregating more than two properties Java 8

To be very simple I have 

 class Per{
    int a;
    long b;
    double c;
    String d;
}

Let say I have 3000 Object of Type Per and collected in a List<Per> pers

Now I want to achieve:-

Old way is 

int totalA = 0; long totalB = 0l; long totalC = 0l;
    for (Per per : pers) {
        if (per.d != null && !per.d.trim().equals("")) {
            totalA += per.a;
            totalB += per.b;
            totalC += someOperation(per.c);
        }
    }

someOperation implemention is not important as it may be simple or complex.

How can I achieve this via Java8 streams and lambda expression?

A possible answer would be like this

int totalA = 0; long totalB=0l;
     pers.stream().filter(p->{
         if(p == null || p.d == null || p.d.trim().equals(""))
             return false;
         return true;
     }).forEach(per->{
         totalA += per.a;
            totalB += per.b;
     });

But totalA and totalB must be final or effectively final

Other possibilities in my mind are:

1 re-use the filtered stream using Supplier as suggested then apply map and aggregation operations.

2 Collect the filtered Per and then do forEach

NOTE I'm not doing any kind of grouping here and can't create new Per or update provided objects.

Upvotes: 1

Views: 785

Answers (1)

Flown
Flown

Reputation: 11740

Write your own Accumulator class and a custom Collector, then it's a simple task.

class Accumulator {
  private int a = 0;
  private long b = 0L;
  private double c = 0d;

  public void accumulate(Per p) {
    a += p.a;
    b += p.b;
    c += someOperation(p.c);
  }

  public Accumulator combine(Accumulator acc) {
    a += acc.a;
    b += acc.b;
    c += acc.c;
    return this;
  }
  // getter, hashCode, ...
}

Accumulator result = pers.stream()
    .filter(p -> p != null && p.d != null && !p.d.trim().isEmpty())
    .collect(Collector.of(Accumulator::new, Accumulator::accumulate, Accumulator::combine));

Upvotes: 6

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