CODEWITHSUNDEEP
pythonfor-loopstrip
user6823145
user6823145

Reputation:

Python for loop - stripping line as you go

I am trying to strip a line of code so that only the comment at the end is saved. Because # signs can be included within "" marks, to do this I am trying to cycle through the line catching pairs of " marks so that it ignores any # marks within "" marks. When I use a code visualiser on my code below, after the second for loop it seems to go pack to processing s as if it has just stripped the first " mark. I can't see what I'm doing wrong here, because the print statement I have included on line 19 shows that s has been stripped to after the second ", but when the code returns to the top, it starts cycling again from after the first ". Any idea of what I am doing wrong here?

s = '("8# " + str" #9 " + line) #lots of hash(#) symbols here'
quoteCount = 0

for char in s:
    if quoteCount%2 == 0:
        if char == '#':
            s = s[s.index('#'):]
            break

    if char == '"':
        quoteCount = quoteCount + 1
        s = s[s.index('"'):]
        s = s.lstrip('"')
        for char in s:
            if char == '"':
                quoteCount = quoteCount + 1
                s = s[s.index('"'):]
                s = s.lstrip('"')
                print(s)
                break

print(s)

Upvotes: 0

Views: 85

Answers (3)

s0hvaperuna
s0hvaperuna

Reputation: 56

Your code is overly complicated so I suggest you use an alternative method to finding the comment like the already mentioned regex one or the one I came up with.

s = '("8# " + str" #9 " + line) #lots of hash(#) symbols here'
s = s[s.rfind('"') + 1:]  # Get to the last quotation mark

if s.find('#') >= 0:  # The first # sign should start the comment if there is one
    s = s[s.find('#'):]

else:
    s = ''  # No comment was found

print(s)

Upvotes: 0

Stavros Georgousis
Stavros Georgousis

Reputation: 32

If I understand your question correctly you only want to keep the last comment (#lots of hash(#) symbols here). To do this you don't need the nested for loop.

s = '("8# " + str" #9 " + line) #lots of hash(#) symbols here'

quoteCount = 0

for char in s:
    if quoteCount%2 == 0:
        if char == '#':
            s = s[s.index('#'):]
            break

    if char == '"':
        quoteCount = quoteCount + 1
        s = s[s.index('"'):]
        s = s.lstrip('"')

print(s)

Upvotes: 2

jas
jas

Reputation: 10865

Easier to remove the quoted strings with a regular expression:

import re
s = '("8# " + str" #9 " + line) #lots of hash(#) symbols here'
pattern = r'"[^"]*"'
s = re.sub(pattern, '', s)
print s[s.index('#'):]

Output:

#lots of hash(#) symbols here

Upvotes: 0

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