CODEWITHSUNDEEP
sqlregexhana
Sarthak Srivastava
Sarthak Srivastava

Reputation: 101

Replacing multiple occurrence by single occurrence in string

I have data like "11223311" and I want all the multiple occurrence to be replaced by single occurrence i.e. the above should turn into '123'. I am working in SAP HANA.

But by using below logic I am getting '1231' from '11223311'.

SELECT  REPLACE_REGEXPR('(.)\1+' IN '11223331' WITH '\1' OCCURRENCE ALL)  FROM DUMMY;

Upvotes: 6

Views: 3323

Answers (2)

David דודו Markovitz
David דודו Markovitz

Reputation: 44921

Please try this

SELECT  REPLACE_REGEXPR(concat(concat('[^','11223331'),']') IN '0123456789' WITH '' OCCURRENCE ALL)  
FROM    DUMMY;

Upvotes: 0

djk
djk

Reputation: 973

Your regular expression only replaces multiple consecutive occurrences of characters; that's what the \1+ directly after it's matching (.) is doing.

You can use look-ahead to remove all characters that also occur somewhere after that match. Note that this keeps the last occurrence, not the first:

SELECT  REPLACE_REGEXPR('(.)(?=.*\1)' IN '11223331' WITH '' OCCURRENCE ALL)  FROM DUMMY

This returns: 231

If you want to keep the first occurrence, I don't see a possibility just with one regex (I could be wrong though). Using a look-behind in the same way does not work because it would need to be variable-length, which is not supported in HANA and most other implementations. Often \K is recommended as alternative, but something like (.).*\K\1 wouldn't work with replace all, because all characters before \K are still consumed in replace. If you could run the same regex in a loop, it could work but then why not use a non-regex loop (like a user-defined HANA function) in the first place.

Upvotes: 3

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