Reputation: 872
I want to automate the creation of "directory variables" from a set of URIS until the maximum number of directories is reached.
For example, if I had 4 directories from URI: "/A/B/C/17628.html"
, I would want to create the following variables:
path_1 = "A"
path_2 = "B"
path_3 = "C"
path_4 = "17628.html"
But if I had : "/A/D/E/F/178.html"
:
path_1 = "A"
path_2 = "D"
path_3 = "E"
path_4 = "F"
path_5 = "178.html"
It's probable to have a URI with many directories (up to 20). To avoid creating all these variables by hand, I want to define them using the for loop (or another option). It's possible to use this loop in BigQuery?
Upvotes: 0
Views: 739
Reputation: 172974
Consider below version
#standardSQL
WITH yourTable AS (
SELECT '/A/B/C/17628.html' AS uri UNION ALL
SELECT '/A/D/E/F/178.html' AS uri
)
SELECT uri, CONCAT('path_', CAST(1 + OFFSET AS STRING)) AS pos, path
FROM yourTable, UNNEST(SPLIT(REGEXP_EXTRACT(uri, r'/(.*)/'), '/')) path WITH OFFSET
ORDER BY uri, OFFSET
result is :
uri pos path
/A/B/C/17628.html path_1 A
/A/B/C/17628.html path_2 B
/A/B/C/17628.html path_3 C
/A/D/E/F/178.html path_1 A
/A/D/E/F/178.html path_2 D
/A/D/E/F/178.html path_3 E
/A/D/E/F/178.html path_4 F
In most practical cases, having such a flattened schema versus pivoted - is much more easier to deal (query) with
In case if you still want to pivot above result - see one of my many answers on that topic - Transpose rows into columns in BigQuery (Pivot implementation)
Upvotes: 1
Reputation: 33705
You need to specify columns in the select list explicitly; it isn't possible for columns themselves to be dynamic. If you are okay with getting the results back as an array, you could do something like this:
#standardSQL
WITH T AS (
SELECT '/A/B/C/17628.html' AS path UNION ALL
SELECT '/A/D/E/F/178.html' AS path
)
SELECT
ARRAY(SELECT IFNULL(subpaths[SAFE_OFFSET(x)], '')
FROM UNNEST(GENERATE_ARRAY(0, 19)) AS x) AS paths
FROM (
SELECT SPLIT(path, '/') AS subpaths
FROM T
);
If you wanted explicit path_1
, path_2
, etc. columns you could do:
#standardSQL
WITH T AS (
SELECT '/A/B/C/17628.html' AS path UNION ALL
SELECT '/A/D/E/F/178.html' AS path
)
SELECT
subpaths[SAFE_OFFSET(1)] AS path_1,
subpaths[SAFE_OFFSET(2)] AS path_2,
subpaths[SAFE_OFFSET(3)] AS path_3,
subpaths[SAFE_OFFSET(4)] AS path_4,
subpaths[SAFE_OFFSET(5)] AS path_5,
subpaths[SAFE_OFFSET(6)] AS path_6,
subpaths[SAFE_OFFSET(7)] AS path_7,
subpaths[SAFE_OFFSET(8)] AS path_8,
subpaths[SAFE_OFFSET(9)] AS path_9,
subpaths[SAFE_OFFSET(10)] AS path_10,
subpaths[SAFE_OFFSET(11)] AS path_11,
subpaths[SAFE_OFFSET(12)] AS path_12,
subpaths[SAFE_OFFSET(13)] AS path_13,
subpaths[SAFE_OFFSET(14)] AS path_14,
subpaths[SAFE_OFFSET(15)] AS path_15,
subpaths[SAFE_OFFSET(16)] AS path_16,
subpaths[SAFE_OFFSET(17)] AS path_17,
subpaths[SAFE_OFFSET(18)] AS path_18,
subpaths[SAFE_OFFSET(19)] AS path_19,
subpaths[SAFE_OFFSET(20)] AS path_20
FROM (
SELECT SPLIT(path, '/') AS subpaths
FROM T
);
Since I didn't want to write that list by hand, I ran a simple one-liner in my terminal:
for i in `seq 1 20`; do echo "subpaths[SAFE_OFFSET($i)] AS path_$i,"; done
Upvotes: 0