Reputation: 155
I have the following table in excel:
Col1 Col2 Col3 Col4 Col5 Col6
43401 17 #N/A 17 #N/A 43401
43480 17 #N/A 17 #N/A 43480
44501 #N/A #N/A #N/A #N/A
97590 #N/A #N/A #N/A #N/A
00475 #N/A #N/A 8 #N/A
The formula is supposed to check if any of the cols(1-5) is not #N/A, then fetch corresponding Col1 value, if not put a blank. The formula that am currently using is giving me an error or row 5 as it has the value 8 in there and should give me back the corresponding Col1 value.
This the formula that am currently using:
=IFERROR(IF(G2<>"#N/A",F2,IF(H2<>"#N/A",F2,IF(I2<>"#N/A",F2,IF(J2<>"#N/A",F2,0)))),"")
In this formula above G2 is col2, row1 and F2 is col1, row 2...and so on.
Any help on why its happening?
Upvotes: 1
Views: 90
Reputation: 371
This is happening because of "#N/A".
IFERROR function traps and handles errors produced by other formulas or functions so it specifically checks for the following errors: #N/A, #VALUE!, #REF!, #DIV/0!, #NUM!, #NAME?, or #NULL!.
So Whenever your functions check for "#N/A" to be true it throws an error and print a blank space.
Either change "#N/A" to "N/A" or use formula below
=IF(OR(NOT(ISNA(G2)),NOT(ISNA(H2)),NOT(ISNA(I2)),NOT(ISNA(J2))),F2,0)
It will give you this output
Col1 Col2 Col3 Col4 Col5 Col6
43401 17 #N/A 17 #N/A 43401
43480 17 #N/A 17 #N/A 43480
44501 #N/A #N/A #N/A #N/A 0
97590 #N/A #N/A #N/A #N/A 0
475 #N/A 8 #N/A #N/A 475
Upvotes: 0
Reputation: 35915
Try this
=IF(COUNTIF(G2:J2,"#N/A")<4,F2,"")
In your current formula the #N/A leads to error results in the IF statement, and your outer IfError just returns the blank.
Your logic can be expressed differently by counting the NA values. If there are fewer than four, one of them cannot be NA, so then return the value from column F.
Upvotes: 1