CODEWITHSUNDEEP
javaconstructor
Prasad
Prasad

Reputation: 956

Can we invoke a constructor without creating its object

What is happening in this code? I want to display the output as "Printing data ASD" without invoking the constructor.

The child class:

package com.javatraining;

public class test1 extends test2{

    public static void main(String[] args) {
        disp();
    }
}

The parent class:

package com.javatraining;

public class test2
{
    public static String name;  

    public test2(){
        name="ASD";
    }

    public static void disp(){
        //test2 t=new test2();
        System.out.println("Printing data "+name);
    }
}

Upvotes: 2

Views: 5018

Answers (5)

Manjunath
Manjunath

Reputation: 1

No, Without the creation of an object we cannot invoke a constructor

Upvotes: 0

AADProgramming
AADProgramming

Reputation: 6335

You don't have to invoke the constructor of parent class at all, if all you want in your child class is an initialised value of name class member, then you can do the declaration + initializations in one go as below.

public static String name = "ASD";

The above style makes it clear at a glance how the variable is initialised and it will also print the expected output.

Of course, if the initialization value is different in different constructors, you must do it in the constructor. You can read more about object initialisation in this article.

Upvotes: 0

Prashant Prabhakar Singh
Prashant Prabhakar Singh

Reputation: 1190

NO. You can't invoke a constructor without creating an object.
Unless you create object of test2 by test2 = new test2();, you will get null in name.

The only way you would have invoked a constructor if it was static, but constructors in Java can't be static. So you have create an object to invoke constructor.

Upvotes: 0

IfOnly
IfOnly

Reputation: 540

public class MainJava extends Test{

    public static void main(String[] args){
        //Option 1
        disp();

        //Option 2
        name = "ABCD";
        disp();

        //Option 3
        new Test();
        disp();
    }

    }

    class Test {
    public static String name = "TEMP";

    public Test() {
        // Will not get called. Unless you create Object
        name = "ASD";
    }

    public static void disp() {
        System.out.println("Printing Data " + name);
    }
}

Upvotes: 0

Tanu Garg
Tanu Garg

Reputation: 3067

Assign a value to the name object of test 2 class. It will work.

public static void main(String[] args) {
        test2.name = "ASD";
        disp();
    }

Upvotes: 1

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