CODEWITHSUNDEEP
javaregexvalidationandroid-edittext
nazanin
nazanin

Reputation: 749

regular expression not work in android

Hi I want to match first name character by character but this make a error , this is my code:

int length = input.length();
for (int i = 0; i < length; i++){
    char ch = input.charAt(i);
    String regex ="^[_\\s]||[آ-ی]$";
    Matcher matcher = Pattern.compile( regex ).matcher(ch);

and this is my complete code:

public class MainActivity extends AppCompatActivity {
    EditText editText;
    Button button;
    String input;
    String result;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        editText = (EditText)findViewById(R.id.edt);
        button = (Button)findViewById(R.id.btn);
        button.setOnClickListener(new View.OnClickListener() {
            @SuppressLint("ShowToast")
            @Override
            public void onClick(View v) {
               input = editText.getText().toString();
                check_reg();
            }
        });

    }
    public  boolean check_reg(){
        int length = input.length();
        for (int i = 0; i < length; i++){
            char ch = input.charAt(i);
            String regex ="^[_\\s]||[آ-ی]$";
            Matcher matcher = Pattern.compile( regex ).matcher(ch);
            if (matcher.find( ))
            {
                result = matcher.group();
                Toast.makeText(MainActivity.this, "match", Toast.LENGTH_SHORT).show();
            }
            else
            {
                Toast.makeText(MainActivity.this, "no match", Toast.LENGTH_SHORT).show();
            }

        }
        return false;
    }
}

and this is a image of my problem:

enter image description here

Upvotes: 2

Views: 1759

Answers (2)

dsh
dsh

Reputation: 12214

The compiler is telling you that you must pass a String to the method matcher(). You can not pass a char to it.

You can create a String of length one if that is what you want.

You can use the regular expression in a more natural way and let it do the matching for you. For example:

public  boolean check_reg(){
    String regex ="^(?:[_\\s]||[آ-ی])+$";
    Matcher matcher = Pattern.compile( regex ).matcher(input);
    if (matcher.find( ))
        {
            result = matcher.group();
            Toast.makeText(MainActivity.this, "match", Toast.LENGTH_SHORT).show();
            return true;
        }
        else
        {
            Toast.makeText(MainActivity.this, "no match", Toast.LENGTH_SHORT).show();
            return false;
        }
}

This pattern will match, character-by-character, the entire input string.

Upvotes: 1

m_callens
m_callens

Reputation: 6360

The problem is that you are passing a char type to the <Pattern>.matcher() method, which only accepts types String or CharSequence. Here are the docs that explain it.

char ch = input.charAt(i);
String regex ="^[_\\s]||[آ-ی]$";
Matcher matcher = Pattern.compile( regex ).matcher(ch);

All you need to do to fix the error is to convert the char ch variable to a string when you pass it to the matcher() method.

char ch = input.charAt(i);
String regex ="^[_\\s]||[آ-ی]$";
Matcher matcher = Pattern.compile(regex).matcher(Character.toString(ch));

Upvotes: 1

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