CODEWITHSUNDEEP
pythonloopswhile-loop
Alex Vincent
Alex Vincent

Reputation: 97

Nested while loop to draw pattern

Hi I'm wondering on how to use a nested loop to draw this pattern on the output

##
# #
#  #
#   #
#    #
#     #
#      #
#       #

I found out how to do it in a loop without nested, but I am curious as to how to draw this using a nested while loop.

while r < 7:
    print("#{}#".format(r * " "))
    r = r + 1

Upvotes: 2

Views: 2448

Answers (4)

Rory Daulton
Rory Daulton

Reputation: 22544

Here is an answer to your actual question: using two nested while loops.

num_spaces_wanted = 0
while num_spaces_wanted < 7:
    print('#', end='')
    num_spaces_printed = 0
    while num_spaces_printed < num_spaces_wanted:
        print(' ', end='')
        num_spaces_printed += 1
    print('#')
    num_spaces_wanted += 1

As the print statements show, this is for Python 3.x. Adjust them for 2.x or add the line from __future__ import print_function to get the 3.x style printing.

Upvotes: 1

B. Eckles
B. Eckles

Reputation: 1644

There are a number of other answers which already correctly answer the question, but I think the following does so in a conceptually more simple way, and it should make it easier to learn from.

spaces = 0

while spaces < 8:
    to_print = "#"

    count = 0
    while count < spaces:
        to_print += " "
        count += 1

    to_print += "#"

    print to_print
    spaces += 1

Upvotes: 0

Peter
Peter

Reputation: 508

The most efficient solution for a nested loop:

#!/bin/python

n = int(raw_input().strip())
for i in xrange(n):
    string = "#" + i * " " + "#"
    print string
    for -1 in xrange(n)
    # Do nothing

Upvotes: -1

Bipul Jain
Bipul Jain

Reputation: 4643

If you intend to do this in python You don't need a nested loop.

Edit With two loops

#!/bin/python
import sys

n = int(raw_input().strip())
for i in xrange(n):
    sys.stdout.write('#')
    for j in xrange(i):
        sys.stdout.write(' ')
    sys.stdout.write('#')
    print

Upvotes: 1

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