CODEWITHSUNDEEP
pythonloopstuples
redbullz010101
redbullz010101

Reputation: 23

iterating through a nested tuple in python

I'm new to python and trying to figure out how to iterate through a nested tuple.

here is a tuple:

x=((1,2,('a', 'b', (6,9,7)), 6,('$','@')))

I'm trying to iterate so I can print each value separately like:

1
2
a
b
6
9
7
6
$
@

Here is my code, please let me know what I'm doing wrong here:

x=((1,2,('a', 'b', (6,9,7)), 6,('$','@')))
f=0
for y in x:
   print(x[f])
   f = f+1

Upvotes: 2

Views: 5961

Answers (2)

Jimbobur
Jimbobur

Reputation: 101

A slight modification of Mohammad Yusuf's answer with a few QOL changes:

  1. Depth tracking/limit, either because you're only interested in layers up to a certain depth or to avoid blowing up on very deep nested tuples.
  2. Configurable depth-based print indenting to help illustrate structure.
def foo(a, depth=0, depth_lim=10, indent_size=1, indent_str="-"):
    # Set up indent and increment depth counter
    indent = indent_str * ((depth) * indent_size)
    depth += 1
    
    #Loop over elements and print if we're not at the depth limit
    if depth <= depth_lim:
        for b in a:
            if isinstance(b, tuple):
                foo(b, depth, depth_lim, indent_size, indent_str)
            else:
                print(indent + str(b))
    else:
        print("Depth limit reached (" + str(depth_lim) + 
              "). Increase depth_lim for deeper printing.")

Example use:

test_tuple = ("a",(("c"),("d"),(("e"),("f"))), "b")
foo(test_tuple, indent_size=2)

Output:

a
--c
--d
----e
----f
b

Upvotes: 0

Mohammad Yusuf
Mohammad Yusuf

Reputation: 17054

You can try with recursion. Check if element is tuple, if it is then make a recursive call to function, if it is not then print it.

x=(((1,2,3,4),2,('a', 'b', (6,9,7)), 6,('$','@')))

def foo(a):
    for b in a:
        if isinstance(b,tuple):
            foo(b)
        else:
            print b
foo(x)

Output:

1
2
3
4
2
a
b
6
9
7
6
$
@

Upvotes: 4

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