CODEWITHSUNDEEP
bashshell
SaiKiran
SaiKiran

Reputation: 6504

How to execute a shell automation task?

In my home directory, I am having a script named blabs and I am passing a file as argument to this bash script like:

./blabs \home\blabs\someFileName

And this will give the results and everything is working fine.

Now I want to automate this task.I have 1000 files in a directory named 2016_10_1 located in home directory.So I want to pass each file as argument to the script.

I wrote a small snippet but it is not working properly.Can anyone help me with this

for i in (find /home/blabs/2016_10_1/ -type f);do "./blabs /home/blabs/2016_10_1/$i";done

Error Log:

-bash: syntax error near unexpected token `('

Upvotes: 0

Views: 72

Answers (3)

J. Chomel
J. Chomel

Reputation: 8393

Yes, as Oliv suggests, you may quick fix this by adding a $:

for i in $(find . -type f); do echo "THIS $i"; done

Upvotes: 1

opentokix
opentokix

Reputation: 853

Find has a built in execute on all found items. So this command will do what you are looking for. 

find /home/blabs/2016_10_1/ -type f -exec /path/to/blabs {} \;

Upvotes: 2

Inian
Inian

Reputation: 85865

See ParsingLs, why you should NOT parse output of find or ls in a for loop.

You use a process substitution syntax(<()) like below,

#!/bin/bash

while IFS= read -r file
do
    /path/to/blabs "$file"
done< <(find /home/blabs/2016_10_1/ -type f)

The output of find is fed one line at time to the while loop, and the script ./blabs executed on it.

Upvotes: 1

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