CODEWITHSUNDEEP
bashshellsedscripting
k189
k189

Reputation: 68

Trying to execute "sed" command but getting "command not found" error

I'm trying to execute the following command:

`sed 's/49%100%/49%!100%/' /etc/nagios/objects/services.cfg`

but I'm getting this error 

-bash: ###############################################################################: command not found

If I try to run it without the back ticks, the command will work.

I've tried the following:

`sed 's/49%100%/49%!100%/' /etc/nagios/objects/services.cfg` 2>&1

`sed 's/49%100%/49%!100%/' /etc/nagios/objects/services.cfg`> /dev/null

but it didn't work.

Upvotes: 1

Views: 7284

Answers (1)

codeforester
codeforester

Reputation: 42999

You don't need back ticks or $() to invoke sed here since your requirement is not to interpret the output of sed as a command.

If your intention is to modify /etc/nagios/objects/services.cfg, you could do this:

sed 's/49%100%/49%!100%/' /etc/nagios/objects/services.cfg > /etc/nagios/objects/services.cfg.new

or, to make an in-place edit (when you are absolutely sure that your sed expression is right):

sed -i 's/49%100%/49%!100%/' /etc/nagios/objects/services.cfg

On BSD systems like macOS, sed -i needs an argument. The command would be:

sed -i '' 's/49%100%/49%!100%/' /etc/nagios/objects/services.cfg

See these posts for more info on back ticks and its more modern form, $():

Upvotes: 6

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