Reputation:
I'm trying to unmarshal a JSON array of the following type:
[
{"abc's": "n;05881364"},
{"abcoulomb": "n;13658345"},
{"abcs": "n;05881364"}
]
into a map[string]string
. This question Golang parse JSON array into data structure almost answered my problem, but mine is a truly map, not an array of maps. Unmarshaling into a []map[string]string
worked but I now get a map of map[string]string
, not a simple map
of string
as it should be
Upvotes: 2
Views: 9545
Reputation: 132018
An alternative (though very similar) to Alex's answer is to define your own type along with an UnmarshalJSON function.
package main
import (
"encoding/json"
"fmt"
)
type myMapping map[string]string
func (mm myMapping) UnmarshalJSON(b []byte) error {
var temp []map[string]string
if err := json.Unmarshal(b, &temp); err != nil {
return err
}
for _, m := range temp {
for k, v := range m {
mm[k] = v
}
}
return nil
}
func main() {
data := []byte(`
[
{"abc's": "n;05881364"},
{"abcoulomb": "n;13658345"},
{"abcs": "n;05881364"}
]`)
resultingMap := myMapping{}
if err := json.Unmarshal(data, &resultingMap); err != nil {
panic(err)
}
fmt.Println(resultingMap)
}
Upvotes: 3
Reputation: 7510
There is no way to do it directly with the json
package; you have to do the conversion yourself. This is simple:
package main
import (
"encoding/json"
"fmt"
)
func main() {
data := []byte(`
[
{"abc's": "n;05881364"},
{"abcoulomb": "n;13658345"},
{"abcs": "n;05881364"}
]
`)
var mapSlice []map[string]string
if err := json.Unmarshal(data, &mapSlice); err != nil {
panic(err)
}
resultingMap := map[string]string{}
for _, m := range mapSlice {
for k, v := range m {
resultingMap[k] = v
}
}
fmt.Println(resultingMap)
}
Output
map[abc's:n;05881364 abcoulomb:n;13658345 abcs:n;05881364]
Upvotes: 7