IGRAPH conversion from R code to Python variant

Question

I am unable to find an equivalent conversion of graph_from_data_frame present in R into something in Python

What I have done is :

graph_from_data_frame(d = dataframe_1[,c("ID_TO","ID_FROM")], directed = TRUE, vertices = sort(unique(unlist(dataframe_1))))

Output of the above :

IGRAPH DN-- 195 201 -- 
+ attr: name (v/c)
+ edges (vertex names):
 [1] 46753->46627 46737->46642 46753->46629 46737->46629 46646->46600  enter code here... (and so on)...

What i tried in python is the following :

# Convert dataframe to matrix
edges = dataframe_1.as_matrix(columns=None)
# create directed graph
MAP = Graph.TupleList(directed=True, edges = edges)  

This gave me below output, which is incorrect (i am getting the output reversed) probably because I was not able to do a sort(unique(unlist())) variant in python. But i am unsure. Output from python code :

IGRAPH DN-- 339 201 --
+ attr: name (v)
+ edges (vertex names):
46627->46753, 46642->46737, 46629->46753, 46629->46737, 46600->46646

I came to know that there is no direct variant of graph_from_data_frame in R into anything in Python, but any lead to this approach and this result is appreciated.

Sample data from dataframe :

 ID_FROM       ID_TO
0    46627          46753
1    46642          46737
2    46629          46753
3    46629          46737
4    46600          46646
5    46552          46633

I have gone through many results from google differentiating about IGRAPH in R vs Python but nothing helped to the sue-case that I am working on.

Answer 1

R Code

library(igraph)
dataframe_1 <- read.table(text='     ID_FROM        ID_TO
                                0    46627          46753
                                1    46642          46737
                                2    46629          46753
                                3    46629          46737
                                4    46600          46646
                                5    46552          46633', header=TRUE)
g <- graph_from_data_frame(d = dataframe_1[,c("ID_TO","ID_FROM")], directed = TRUE, vertices = sort(unique(unlist(dataframe_1))))
plot(g)

Python Code

from igraph import *
import pandas as pd

dataframe_1 = pd.DataFrame({'ID_FROM':[46627, 46642, 46629, 46629, 46600, 46552], 'ID_TO':[46753,46737,46753,46737,46646,46633]})
#print dataframe_1
g = Graph(directed=True)
for index, row in dataframe_1.iterrows():
   g.add_vertex(str(row['ID_FROM']))
   g.add_vertex(str(row['ID_TO']))
   g.add_edge(str(row['ID_FROM']), str(row['ID_TO'])) 
g.vs["label"] = g.vs["name"]
plot(g)