CODEWITHSUNDEEP
javahex
Paul
Paul

Reputation: 1734

Java/Android String to Color conversion

I'm making an app and I'd like to be able to set various colors via user input(edittext) and hex values e.g. #eeeeee and so on. Problem is I cannot seem to figure out how to convert them.

If I do something in code like this it works fine: titlebar.setBackgroundColor(0xFF545455);

However if I retrieve a value via the edittext say "545455" I cannot get it work 

          String tbColor = tb_color.getText().toString();             
          String value = "0xFF" + tbColor;  
          int setColor = Integer.valueOf(value);
          titlebar.setBackgroundColor(setColor);

Anyone have any ideas on how to accomplish this?

Upvotes: 9

Views: 16055

Answers (4)

Dan Alboteanu
Dan Alboteanu

Reputation: 10232

here is my function to get colors from ANY string. Eg: "Hello World!" will return you some green color of R G B: 84 181 132 

public static int getColorFromString(String string) {
    int[] RGB = {0,0,0};
    int l = string.length();
    String sub_string_0 = string.substring(0, (int) Math.ceil((double) l / 3));                 // responsable for Red
    int l_0 = sub_string_0.length();
    String sub_string_1 = string.substring(l_0,  l_0 + (int) Math.ceil((double) (l - l_0)/2));  // responsable for Green
    String sub_string_2 = string.substring(l_0 + sub_string_1.length(), string.length());       // responsable for Blue

    String[] sub_string = new String[]{
            sub_string_0,
            sub_string_1,
            sub_string_2
    };
    for(int i = 0; i < sub_string.length; i++) {
        if(sub_string[i].length()==0)
            sub_string[i] = " ";                                                                // we asign a value (a space)
        Log.d("sub_string", i + " " + sub_string[i]);
        for (char c : sub_string[i].toCharArray()) {
            int c_val = Character.getNumericValue(c) - Character.getNumericValue('a');          // for 'a' -> 0     for 'z' -> 25
            if(c_val < 0)                                                                       //  spaces, numbers ...
                c_val= new Random().nextInt(25);                                                //add some salt - a random number
            Log.d("value ", c + " -> " + c_val);
            RGB[i] = RGB[i] + c_val;
        }
    }

    int letters_number = Character.getNumericValue('z') - Character.getNumericValue('a');       //  z - a    35 - 10

    // normalizing
    int R = 255 * RGB[0]/sub_string[0].length()/letters_number;
    int G = 255 * RGB[1]/sub_string[1].length()/letters_number;
    int B = 255 * RGB[2]/sub_string[2].length()/letters_number;
    Log.d("R G B", R +" " + G + " "  + B);

    return Color.rgb(R, G, B);
}

Note: The function does not return the same number(color) each time if your string includes special characters, spaces or numbers. There is some salt there - I asigned random numbers to those characters, just for fun...

Upvotes: 0

jayesh kavathiya
jayesh kavathiya

Reputation: 3541

StringBuffer hexString = new StringBuffer();
hexString.append(Integer.toHexString(0xFF);
System.out.print(hexString.toString());

Upvotes: 0

Shadi
Shadi

Reputation: 2246

What about titlebar.setBackgroundColor(Color.parseColor("#545455"));

Upvotes: 51

thejh
thejh

Reputation: 45568

http://download.oracle.com/javase/1.4.2/docs/api/java/lang/Integer.html#parseInt(java.lang.String, int)

For example:

titlebar.setBackgroundColor(Integer.parseInt("545455", 16)+0xFF000000);

Upvotes: 20

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