CODEWITHSUNDEEP
phpapilaravel-5laravel-passport
Ariful Haque
Ariful Haque

Reputation: 3750

Laravel 5.3 with Passport: Get Current User with Personal Access Token

I've installed Passport with Laravel 5.3 and configured to use Personal Access Token. I am sending username and password to `/oauth/token' route and get a token. Everything is fine until here.

But if I want to get current logged in user with $user = Auth::user(); as we used to get it before, I get null value as Laravel don't keep any session for API Token. In this situation, how can I get the current user? Can I modify any file to get the current user along with token?

Thanks In Advance Arif

Upvotes: 4

Views: 3030

Answers (1)

4levels
4levels

Reputation: 3234

First of all, I'm using Passport with password_clients in an OAuth2 flow. My Lumen/Laravel version in composer is 5.4.*

I'm using the following statement in my Lumen application (note I'm not using facades):

$user = app('auth')->guard()->user()

This is probably equivalent to the facade call:

$user = Auth::guard()->user()

Hope this helps..

Kind regards,

PS. To figure what class is returned when not using facades, I find myself doing eg. a echo get_class(app('auth')) to get the class and tell my IDE what kind of variable $auth is..

Snippet from one of my Lumen controllers

$auth = app('auth');
// echo get_class($auth); to get class
// -> \Illuminate\Auth\AuthManager in this case
/* @var $auth \Illuminate\Auth\AuthManager */

$guard = $auth->guard();
// idem as above
/* @var $guard \Illuminate\Auth\RequestGuard */

$user = $guard->user();
/* @var $auth \App\Auth\User */

// this tells Webstorm/Netbeans/.. to consider $auth an instance of AuthManager and enables autocompletion of class methods

Upvotes: 3

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