Basic : Return and stop code execution on JavaScript

Question

I wrote these simple code,

function a()
{
    function b()
    {
        function d()
        {
            if (/*required condition goes here and should stop execution of
              function a()*/)
            {
                return
            }
        }

        d()
    }
    function c()
    {
        alert ('c')
    };
    b();
    c();
}

What I expected is the execution aborts when it meet the required condition on function d() and cancelling the execution of function c(). Otherwise, it runs the remaining function after executing function b().
How can I do that?

Edit: What I actually want to know wheter if the 'return' key colud terminate immediately for the outer function like 'Exit Sub' on VB.Net

Answer 1

You could use the return value for the inner function and use it as flag.

function a() {
    function b() {
        function d() {
            console.log('in d');
            if (true) {
                return;
            }
            return true;
        }
        console.log('in b');
        return d();
    }

    function c() {
        console.log('in c');
        alert('c');
    }

    console.log('in a');
    console.log(b() && c());
}

a();

Answer 2

You'd pass the information that processing should stop out of d and out of b and use it to determine whether to call c:

function a() {
    function b() {
        function d() {
            if (/*some condition*/) {
                return false;       // ***
            }
            return true;            // ***
        }
        return d();                 // ***
    }

    function c() {
        alert('c')
    };

    if (b()) {                      // ***
        c();                        // ***
    }                               // ***
}

Alternately, you could have d throw:

function a() {
    function b() {
        function d() {
            if (/*some condition*/) {
                throw new Error();     // ***
            }
            return;
        }
        d();
    }

    function c() {
        alert('c')
    };

    b();
    c();
}

...but then a would throw rather than completing normally (though you could add a try/catch). Also, throwing is relatively expensive and not for normal branching purposes.