CODEWITHSUNDEEP
pythonpython-3.x
Simplebox gg
Simplebox gg

Reputation: 33

python 3 finding and printing integers from a text file

My text file is laid out like this:

1,jack,Jackson,16,won

2,Dex,Craz,17,loss

3,Bree,Lopson,20,

4,her,ber,12,loss

5,say,huy,34,

6,lol,asw,23,won

7,dert,ker,30,loss

8,far,sas,11,

9,ger,xza,15,

10,yui,caer,66,won

11,opl,guyh,45,

and what I'm trying to do is have the user input a number that they would like to see and print out the information corresponding to that number.

This is my code:

numb = input('Input Line: ')
fiIn = open('Prac.txt').readlines()
for lines in fiIn:
   if numb == lines[0]:
      data = lines.split(',')
      print ('|{0[0]:<15}|{0[1]:<15}|{0[2]:<15}|{0[3]:<15}|{0[4]:<15}'.format(data))

but it doesn't only print the number I want but also other numbers. For example: if I input 1 it would output 1, 10 and 11 not just 1. Any idea on how to do this?

Upvotes: 1

Views: 48

Answers (2)

ZdaR
ZdaR

Reputation: 22954

The error is in the comparison line if numb == lines[0]: where you are checking the input string with the first character of the line and hence it matches all the lines starting with 1, What you need to do is split the line on , and then compare the first element as :

numb = input('Input Line: ')
fiIn = open('Prac.txt').readlines()
for lines in fiIn:
   if numb == lines.split(",")[0]:
      data = lines.split(',')
      print ('|{0[0]:<15}|{0[1]:<15}|{0[2]:<15}|{0[3]:<15}|{0[4]:<15}'.format(data))

Upvotes: 1

Lafexlos
Lafexlos

Reputation: 7735

split() lines first, then check if the first item is your number.

for lines in fiIn:
   data = lines.split(',')
   if numb == data[0]:
       print ('|{0[0]:<15}|{0[1]:<15}|{0[2]:<15}|{0[3]:<15}|{0[4]:<15}'.format(data))

Upvotes: 1

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