CODEWITHSUNDEEP
pythonbashpython-2.7execv
user1763510
user1763510

Reputation: 1260

Restart of python script within script with same python version

I am running a python program on a server, and on my account on the server I have the python version set in .bashrc file as follows:

alias python="python2.7"

I have a python script that I would like to be able restart itself. It works fine locally, but when I restart it on the server, it works once, and then switches to a different version of python. I have the following function:

def restartScript(self):
  print("Restarting server")
  print(sys.executable,['python']+sys.argv)
  os.execv(sys.executable,['python']+sys.argv)

The first time I try to restart it prints the following:

/usr/local/bin/python2.7 ['python', 'server.py']

However the second time I run the server, it prints the following:

/usr/local/bin/python ['python', 'server.py']

This also gives an error, because I am using a module that is installed for /usr/local/bin/python2.7 but isn't installed for /usr/local/bin/python.

Is there an easy way to make sure that the server always restarts with /usr/local/bin/python2.7? I would like to make it flexible so that someone can use this restart whether they have defined their default version of python in .bashrc or are using a virtual environment. Also would like it work if they are using python 3 or python 2.

Upvotes: 0

Views: 764

Answers (2)

user1763510
user1763510

Reputation: 1260

The following works independent of which python version you are using:

os.execv(sys.executable,[sys.executable.split("/")[-1]]+sys.argv)

Upvotes: 1

happydave
happydave

Reputation: 7187

I feel like I may be misunderstanding something, but I think you just want to pass 'python2.7' as the first element of your list of arguments instead of 'python'. Or if you're not sure what the executable name will be, pass sys.executable.

Upvotes: 0

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