CODEWITHSUNDEEP
arraysbashunix
mattman88
mattman88

Reputation: 495

Remove Beginning And End Of Each Element In Array In Bash

I have a bash array with 3 elements and I need to remove the first X number characters from all the elements and the last Y number of characters from all the elements. How can this be achieved. Example below:

echo ${array[@]}
random/path/file1.txt random/path/file2.txt random/path/file3.txt

I would like this array to become

echo ${array[@]}
file1 file2 file3

How can this be achieved?

Upvotes: 1

Views: 2604

Answers (3)

George Vasiliou
George Vasiliou

Reputation: 6345

This will go with one shot:

$ a=( "/path/to/file1.txt" "path/to/file2.txt" )
$ basename -a "${a[@]%.*}"
file1
file2

Offcourse, can be enclosed in $( ) in order to be assigned to a variable.

Upvotes: 1

chepner
chepner

Reputation: 531205

There's no way to do this in just one step; you can, however, remove the prefixes first, then the suffixes.

array=( "${array[@]##*/" )  # Remove the longest prefix matching */ from each element
array=( "${array[@]%.*}" )  # Remove the shortest suffix match .* from each element

Upvotes: 1

Wrikken
Wrikken

Reputation: 70490

You can still use basic string manipulation there:

echo ${array[@]##*/}

Or, to assign it to the array:

array=(${array[@]##*/})

Upvotes: 1

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