CODEWITHSUNDEEP
linuxshellwhile-loopsh
Mohamed Ali Benmansour
Mohamed Ali Benmansour

Reputation: 343

Shell sh , syntax while(condition)

I am testing a simple program shell(sh).

I am using while loop but it show an error.

./essai.sh: line 5: test: too many arguments

This is the code:

#!/bin/sh

numero=1
max=3
while test [ $numero -le $max ]
do
ping -c 2 127.0.0.1
numero=$(($numero + 1)) 
printf $numero
sleep 5
done

Upvotes: 0

Views: 393

Answers (3)

zzn
zzn

Reputation: 2465

"[]" means "test", So you can change that line to

  while test  $numero -le $max

or

  while [ $numero -le $max ]

BTW: the spaces between "[]" and conditional expression is necessary.

Upvotes: 3

BOC
BOC

Reputation: 1139

The test keyword has to be removed:

while [ $numero -le $max ]

Do you know also

for numero in $(seq 1 3) ; do echo $numero ; done

Upvotes: 1

Snehal Patel
Snehal Patel

Reputation: 1330

Condition statement is wrong change condition from 

while test [ $numero -le $max ]

to 

while [ $numero -le $max ]

Upvotes: 1

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