CODEWITHSUNDEEP
swift
Olivier
Olivier

Reputation: 655

Swift sample code using switch, case and fallthrough

In the following code sample, I don't understand why "Value 7" gets printed instead of "Default". Case 7, i.e. x=7 is not met because x=6, so why does "Value 7" get printed instead of being skipped and the execution falling through to default?

let x = 6
 
switch x {
     
case 0...5:
    println("0 through 5")
     
case 6:
    fallthrough
     
case 7:
    println("Value 7")
     
default:
    println("Default")
}

Upvotes: 2

Views: 1660

Answers (1)

theMikeSwan
theMikeSwan

Reputation: 4729

When x = 6 the switch statements finds the case for 6 then it 'falls through' to the next case not the default one. If you want the case for 6 to execute the code under default remove that case as it does nothing. If you plan to add some code to the case for 6 then make it the last one before default so it falls through to the place you want.

Upvotes: 5

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