Reputation: 26489
Say I have the following link:
<li class="hook">
<a href="i_have_underscores">I_have_underscores</a>
</li>
How would I remove the underscores only in the text and not the href? I have used str_replace()
, but this removes all underscores, which isn't ideal.
So basically I would be left with this output:
<li class="hook">
<a href="i_have_underscores">I have underscores</a>
</li>
Upvotes: 0
Views: 849
Reputation: 2255
You can use a HTML DOM parser to get the text within the tags, and then run your str_replace()
function on the result.
Using the DOM Parser I linked, it is as simple as something like this:
$html = str_get_html(
'<li class="hook"><a href="i_have_underscores">I_have_underscores</a></li>');
$links = $html->find('a'); // You can use any css style selectors here
foreach($links as $l) {
$l->innertext = str_replace('_', ' ', $l->innertext)
}
echo $html
//<li class="hook"><a href="i_have_underscores">I have underscores</a></li>
That's it.
Upvotes: 6
Reputation: 3247
It's safer to parse HTML with DOMDocument instead of regex. Try this code:
<?php
function replaceInAnchors($html)
{
$dom = new DOMDocument();
// loadHtml() needs mb_convert_encoding() to work well with UTF-8 encoding
$dom->loadHtml(mb_convert_encoding($html, 'HTML-ENTITIES', "UTF-8"));
$xpath = new DOMXPath($dom);
foreach($xpath->query('//text()[(ancestor::a)]') as $node)
{
$replaced = str_ireplace('_', ' ', $node->wholeText);
$newNode = $dom->createDocumentFragment();
$newNode->appendXML($replaced);
$node->parentNode->replaceChild($newNode, $node);
}
// get only the body tag with its contents, then trim the body tag itself to get only the original content
return mb_substr($dom->saveXML($xpath->query('//body')->item(0)), 6, -7, "UTF-8");
}
$html = '<li class="hook">
<a href="i_have_underscores">I_have_underscores</a>
</li>';
echo replaceInAnchors($html);
Upvotes: 2