CODEWITHSUNDEEP
shellvariablesunix
mbreddy77
mbreddy77

Reputation: 51

Working with variables in Unix

I have a variable $x that has a value of a position of an argument to the script (say 8). I need to capture the value in the 8th argument (say 1) into another variable y and be able to use that as variable $y ($1) to refer to a column in a file.

Upvotes: 0

Views: 30

Answers (1)

codeforester
codeforester

Reputation: 42999

You can use the indirect reference ${!var} to do this:

set one two three four five six seven eight
x=8
y=${!x}
echo $y

You get this output:

eight

Upvotes: 1

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