CODEWITHSUNDEEP
pythonregex
Tag
Tag

Reputation: 51

Re.findall returning only the first match in Python 2.7

When a sentence in my_file begins with a word followed by a digit, such as "City1", and there is another sentence in my_file beginning with "City2", the following code only returns the first sentence:

description = re.findall("\n"+i+"[\s\,\d\(].*\.\n", my_file) #i equals 'City'
if description:
        for d in description:
            d = d.replace('\n', ' ')
            bufferlist.append(d)
            bufferlist[:] = unique( bufferlist ) #unique is a function removing duplicates from a list while keeping its order
            my_string = ' '.join(bufferlist)
            del bufferlist[:]
else:
        my_string = '0'

Why can't I get both the first and the second sentence in my_string?

EDIT The problem, or a part of it, was del bufferlist[:]. This prevented the desired pile-up of matches in every iteration. The bufferlist has to be deleted after the loop.

Upvotes: 1

Views: 1055

Answers (1)

vks
vks

Reputation: 67968

(?:^|(?<=\n))City[\s\,\d\(].*\.(?=\n|$)

Try this.You are consuming \n which might not be leaving it for others to match.

See demo.

https://regex101.com/r/VIXyar/1

Upvotes: 1

Related Questions