CODEWITHSUNDEEP
pythonpython-3.xsyntax-errorany
Micah Young
Micah Young

Reputation: 171

'any' doesn't raise error?

I was playing around then I noticed this:

>>> l = input().split()
1 25 11 4
>>> any(s == s[::-1] for s in l)
True
>>> s == s[::-1] for s in l
SyntaxError: invalid syntax
>>>

Why does any(s == s[::-1] for s in l) work if s == s[::-1] for s in l itself would raise error?

Upvotes: 0

Views: 65

Answers (2)

Darkaird
Darkaird

Reputation: 2890

To complete Dan D. answer,

(s == s[::-1] for s in l)

is like :

def your_function():
    for s in l:
        yield s == s[::-1]

Upvotes: 1

Dan D.
Dan D.

Reputation: 74655

any(s == s[::-1] for s in l)

is the same as:

any((s == s[::-1] for s in l))

and:

(s == s[::-1] for s in l)

is not a syntax error. It is a generator expression. As you have found parenthesis are required around generator expressions except when they occur as the only argument to a function call.

Upvotes: 3

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