Reputation: 1115
What went wrong in this code? I ready many post here on this issue but can't fix my error. I have the following.
HTML Code
<div id="successMessage" style="display:none;"> It worked </div>
<div id="failMessage" style="display:none;"> It failed </div>
<div container>
<div class="modal">
<form>
....
</form>
</div>
</div>
PHP Code
if(!$stmnt->execute()){
echo "Failed!";
}else{
echo "Inserted";
}
AJAX Code
success: function(data){
viewData();
if (data=="Failed!") {
console.log(data);
$("#failMessage").show();
} else if(data=="Inserted"){
console.log(data);
$("#successMessage").show();
}
}
Problem: I would like to display the error in the page not in console. I want to inform the user. Why is it not working with $("#successMessage").show();
?
PS: I am using Bootstrap. Also how can I show my messages using one(1) div="msg"
tag?
Upvotes: 0
Views: 451
Reputation: 759
Found a mistake in your code
PHP Code
if(!$stmnt->execute()){
echo "Failed!"; // Check the exclamation mark
}else{
echo "Inserted";
}
AJAX Code
success: function(data){
viewData();
$('#addData').modal('hide');//close the modal.
if (data=="Failed!") { // Add an exclamation mark to correct code
$("#failMessage").show();
//console.log(data); is showing message from PHP
} else if (data=="Inserted") { // Change this else to else if
$("#successMessage").show();
//console.log(data); is showing message from PHP
}
Change "Failed
" in ajax to "Failed!
". Also, change the else
to correct format of else if
Upvotes: 1