Reputation: 17
I have one table its name - UserData and its contain one column name -
UserInfo.
UserInfo column contains following values likes
demo.acc.in
swiss.com.au
austa.edu.co
I want to extract the following information from it...
Output
demo
swiss
austa
Thanks in advance for help
Upvotes: 0
Views: 42
Reputation: 1270421
You can use left()
and charindex()
:
select left(userinfo, charindex('.', userinfo + '.') - 1)
Note that the + '.'
means that this will work even when userinfo
does not contain a space.
Upvotes: 5