CODEWITHSUNDEEP
pythonlistpython-3.xfor-looptuples
virgiliocyte
virgiliocyte

Reputation: 175

Accessing/using elements from lists of tuples python 3.x

I'm new to python and I'm trying to figure out how to access and use integers stored in lists of tuple pairs (a, b), such that I can divide a by b and if it meets a criteria, I append the tuple to a new list and I count the tuple. I would like to do this using only basic functions and for-loops.

I borrowed some code from another stackoverflow question that I used to create the list of tuples from two separate integer lists of different sizes as such: 

list_a = list(range(10, 51))

list_b = list(range(1, 21))

new_tuple_list = []
new_tuple_count = 0

for i, a in enumerate(list_a):
    new_tuple_list.append((a, list_b[i % len(list_b)]))
    divisors_count += 1

print ("New tuple count: ", new_tuple_count)
print (new_tuple_list)

This gives me: New tuple count: 41

[(10, 1), (11, 2), (12, 3), (13, 4), (14, 5), (15, 6), (16, 7), (17, 8), (18, 9), (19, 10), (20, 11), (21, 12), (22, 13), (23, 14), (24, 15), (25, 16), (26, 17), (27, 18), (28, 19), (29, 20), (30, 1), (31, 2), (32, 3), (33, 4), (34, 5), (35, 6), (36, 7), (37, 8), (38, 9), (39, 10), (40, 11), (41, 12), (42, 13), (43, 14), (44, 15), (45, 16), (46, 17), (47, 18), (48, 19), (49, 20), (50, 1)]

But I want to know if I divide 10 by 1 from (10, 1), 11 by 2, etc., will I get an integer, and if so, I want to add that to a new list and count the number of tuple pairs this is true for. I have tried this:

tuple_test = [(10,1), (11,2)]
def find_divisors (x):

    NUM_tuples = []
    tuples_count = 0

    for x[0] in pairs:
        for x[1] in pairs:
            if x[0] / x[1] % 2 == 0:
                NUM_tuples.append(pairs)
                tuples_count += 1
                return (x[0] / x[1] % 2)
    return NUM_tuples
    return tuples_count

 find_divisors(tuple_test)

I have also tried something like this:

def divisors(list_a, list_b):

    test_int = 0
    new_divisors = []

    for a in list_a:
        for b in list_b:
            if a/b % 2 == 0:
                test_int += 1
                new_divisors += (a,b)

    return new_divisors
    return test_int

    NUM_tuples = []
    tuples_count = 0


    for i, c in enumerate(list_a):
        NUM_tuples.append((c, list_b[i % len(list_b)]))
        tuples_count += 1
    return tuples_count
    return NUM_tuples

divisors(list_a, list_b)

any help would be appreciated!

Upvotes: 1

Views: 193

Answers (2)

Steven Summers
Steven Summers

Reputation: 5384

I would also like to add that you can reduce your code to get the original list of tuples to the following using itertools.cycle.

from itertools import cycle

# a and b don't have to be a list unless you need them as a list elsewhere.
a = range(10, 51)
b = range(1, 21)
# cycle the shorter one
tuple_lst = list(zip(a, cycle(b)))

print("New tuple count:", len(tuple_lst))
print(tuple_lst)

Upvotes: 0

Ujjwal
Ujjwal

Reputation: 1859

Try the following : 

a = range(1,20)
b = range(1,5)
c = [(x,y) for x in a for y in b if x%y==0]
print(c)

It gives the following output 

[(1, 1), (2, 1), (2, 2), (3, 1), (3, 3), (4, 1), (4, 2), (4, 4), (5, 1), (6, 1), (6, 2), (6, 3), (7, 1), (8, 1), (8, 2), (8, 4), (9, 1), (9, 3), (10, 1), (10, 2), (11, 1), (12, 1), (12, 2), (12, 3), (12, 4), (13, 1), (14, 1), (14, 2), (15, 1), (15, 3), (16, 1), (16, 2), (16, 4), (17, 1), (18, 1), (18, 2), (18, 3), (19, 1)]

You can easily adapt this for your program I think !!

PS : The length of c above will give you the tuple count.

Upvotes: 3

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