CODEWITHSUNDEEP
javavariablesnumbers
Christos Antonopoulos
Christos Antonopoulos

Reputation: 47

What is type variable in java -(number)d

I can't cast this value as Integer and I can't file what type is (I know is String) but I need convert as number, Interger.parse() does not work I get Exception.

String str = "-10d";
Interger.parse(str); //I get Exception

Upvotes: 0

Views: 3029

Answers (4)

wake-0
wake-0

Reputation: 3968

Here you get the double value:

String str = "-10d";
Double d = Double.parseDouble(str);
System.out.println(d);

And to get the integer value:

int intValue = d.intValue();

Other solutions, which change the input string for the parse method are (I don't recommend them): 

int x = Integer.valueOf(str.substring(0, str.length() - 1));
int y = Integer.valueOf(str.replace('d', ' ').trim());

Upvotes: 1

Youcef LAIDANI
Youcef LAIDANI

Reputation: 59968

You get Exception because it is not correct there are no Interger.parse(str); i think you want to make :

Integer.parseInt(str);

But your string have d and d work with Double not with Integer so instead use this :

String str = "-10d";
Double.parseDouble(str);

Upvotes: 1

Noir
Noir

Reputation: 78

String str = "-10b" (mentioned in question) or "-10d" (mentioned in title)?

If what you mean is -(number)d,then it is double.
try 

double b = Double.parseDouble("-10d");

instead of using Integer.parseInt

Upvotes: 1

anacron
anacron

Reputation: 6721

You can use this to convert your String to int.

String str = "-10d";
int i = Double.valueOf(str).intValue();

Hope this helps!

Upvotes: 1

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