CODEWITHSUNDEEP
nullscanf
A.A
A.A

Reputation: 11

Why am I getting (null) after scanf?

I don't understand why am I getting (null) after running this code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
    char input;

    printf("enter string: ");
    scanf("s", input);

    printf("%s", input);
}

enter image description here

Why am I getting (null) after scanf?

Upvotes: 1

Views: 827

Answers (2)

BusyProgrammer
BusyProgrammer

Reputation: 2791

The problem in your answer is that you have a char variable input, but it is not initialized with a length. As a result, it prints (NULL). To overcome this issue, you should change your declaration of input to something like:

 char input[30];

This way, you can store up to 30 chars in your input variable. Note that I used 30 as an example; you can use any value of your choice here.

Secondly, the line:

 scanf("s", input);

Is invalid; it should be:

 scanf("%s", input);

Because %s is a placeholder for the variable given after the string; here it is input. %s refers to a placeholder for a string or char[] data-type s is the correct syntax.

** As an aside, since you want to read an entire sentence as input, you should know that your code will only work for accepting input until a spacebetween the first word and the next one, because scanf() does not read a space. To learn more anout using strings, refer to this link: C Programming Strings

Good luck!

Upvotes: 2

Stobal45
Stobal45

Reputation: 13

Try giving a length for yout char, i.E. char[25]. The char now keeps a single character.

Upvotes: 1

Related Questions