Reputation: 124
Any opinions on this? When the user presses the button the initially hidden div must show itself on the page.
<!DOCTYPE html>
<html>
<head>
<style>
div {
display: none;
}
</style>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js">
function show() {
$("div").toggle();
}
</script>
</head>
<body>
<p>Animals are cute!</p>
<div><p>Some text gonna blow up some pixels!</p></div>
<button onclick="show()">Click</button>
</body>
</html>
The exactly written error in the Console:
ReferenceError: show is not defined[Learn More
Upvotes: 0
Views: 204
Reputation: 1
function show() {
$(".any-text").toggle();
}
.any-text {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<html>
<body>
<p>Animals are cute!</p>
<div class="any-text"><p>Some text gonna blow up some pixels!</p></div>
<button onclick="show()">Click</button>
</body>
</html>
Upvotes: 0
Reputation: 8589
Move the inline script into its own tag. You can't use an external script and inline script in the same tag.
So:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script>
function show() {
$("div").toggle();
}
</script>
Upvotes: 3