ba11b0y
ba11b0y

Reputation: 169

How do I access member variables from one class into other using friend functions in C++?

I am using fried functions for the very time and was assigned to complete an incomplete code using friend functions as below.

//CODE GIVEN IN THE QUESTION NOT MEANT TO BE EDITED
#include<iostream>
using namespace std;
class store_keeper;
class item
{
    char prod_name[30];
    char prod_code[10];
    float prod_price;
    int stock_In_Hand;
    public:
    void get();
    void print()const;
    friend class store_keeper;
};
class store
{
    int num_Of_Items;
    item items[20];
    public:
    void get_details();
    void print_details() const;
    friend class store_keeper;
};
class store_keeper
{
    char name[30];
    char id[10];
    public:
    void get();
    void print();
    void stock_mgmt(store &);
};
//MY CODE
void item::get()
{
cin>>prod_name>>prod_code>>prod_price>>stock_In_Hand;
}
void item::print() const
{
    cout<<prod_name<<prod_code<<prod_price<<stock_In_Hand;
}
void store::get_details()
{
    cin>>num_Of_Items;
    for(int i=0;i<num_Of_Items;i++)
    {
        items[i].get();
    }

}
void store::print_details() const
{
    for(int j=0;j<num_Of_Items;j++)
    {
        items[j].print();
    }

}
void store_keeper::stock_mgmt(store &s)
{
    for(int k=0;k<s.num_Of_Items;k++)
    {
        if(items[k].stock_In_Hand<10)
        {
            s.print_details();
        }
    }
}
//CODE GIVEN IN THE QUESTION NOT MEANT TO BE EDITED
main()
{
    store s;
    store_keeper sk;
    s.get_details();
    sk.stock_mgmt(s);
}

I had to display the details of the item for which the stock in hand is less than 10.I am getting an error that num_Of_Items was not declared in this scope and suggest any edits if any required.Thanks.

Upvotes: 0

Views: 928

Answers (1)

marcinj
marcinj

Reputation: 49986

There are few problems with your code, and they are all located in this function:

void store_keeper::stock_mgmt(store &s)
                                     ^ ~~~~~~ 1
{
    for(int k=0;k<s.num_Of_Items;k++)
    {             ^^^^^^^^^^^^^^~~~~~~~~~~~~~ 2 
        if(s.items[k].stock_In_Hand<10)
        {  ^^ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 3
            s.items[k].print();
        }   ^ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 4
    }
}

1 - you need to give name to this parameter as it is needed inside your function

2 - when compiler see store_keeper::num_Of_Items it thinks you want to access a static variable of name num_Of_Items inside store_keeper class, but there is no such variable. What you want here is to use s. to read num_Of_Items from s which is of type store. You have befriended store_keeper with store so this is legal

3 and 4 - items is a field in store class, which is provided to your function as a parameter s, so use s. to access it.

And finally item has a print and not print_details

This will allow your code to compile, but probably more work is needed to make it work as expected.

Upvotes: 1

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