Reputation: 53
select 'Test '+m.testname+' '+
Case
When m.value = 'ttttt' Then 'tt'
When m.styleName = 'ppppp' Then 'pp'
When m.styleName = 'qqqqq' Then 'qq'
When m.styleName = 'yyyyyy' Then 'yy'
Else ''
End from testtable m where m.id=10'
This is my query, i need to check the length of string formed after case statement.if the length greater than 35 then i want to remove charecters from "m.testname" field. Thanks for your help.
Upvotes: 1
Views: 35
Reputation: 70648
You can use your current query as a derived table:
select YourString,
LEN(YourString) [Length],
Case
When LEN(YourString) > 35 THEN REPLACE(YourString,testname,'')
Else YourString
End YourNewString
from ( select 'Test '+m.testname+' '+
Case
When m.value = 'ttttt' Then 'tt'
When m.styleName = 'ppppp' Then 'pp'
When m.styleName = 'qqqqq' Then 'qq'
When m.styleName = 'yyyyyy' Then 'yy'
Else ''
End YourString,
m.testname
from testtable m
where m.id=10) a
;
Or you can use a CTE:
WITH CTE AS
(
select 'Test '+m.testname+' '+
Case
When m.value = 'ttttt' Then 'tt'
When m.styleName = 'ppppp' Then 'pp'
When m.styleName = 'qqqqq' Then 'qq'
When m.styleName = 'yyyyyy' Then 'yy'
Else ''
End YourString,
m.testname
from testtable m
where m.id=10
)
select YourString,
LEN(YourString) [Length],
Case
When LEN(YourString) > 35 THEN REPLACE(YourString,testname,'')
Else YourString
End YourNewString
from CTE;
Upvotes: 1