CODEWITHSUNDEEP
python
user7644228
user7644228

Reputation: 1

comparing two lists of lists with different sizes

I need to compare elements from individual list of lists. For example here are my two list:

listing = [['tl.48', 'tl.49', 'tl.57'], ['tl.23', 'tl.45', 'tl.12']];
search = [['tl.48','tl.57']];

Now my goal is to look for each item in search into each item in listing and if the two items 'tl.48', 'tl.57' matches the items in listing then I choose that item from the listing and append it in an empty list. listing[0] has a size of 3 elements and search[0][0] and search[0][1] are present at listing[0][0] and listing[0][2]. How can I get listing[0] in a separate list and append it. If listing[0] is of size 4 and search[0][0] and search[0][1] are present in listing[0], I will still add listing[0] to the new list. How can I do it?

Thanks.

Upvotes: 0

Views: 229

Answers (1)

TemporalWolf
TemporalWolf

Reputation: 7952

[lst for lst in listing if all([True if term in lst else False for term in search[0]])]

Result: [['tl.48', 'tl.49', 'tl.57']]

This, for each list in listing, checks if each search term is in the list, only appending it if all such terms are there.

Note: search is a list containing a single list, which is why we use search[0]. If it's just the list of elements, use search instead.

Roughly equivalent to (same result, different method):

result = []
for lst in listing:
    valid = True
    for term in search[0]:
        if term not in lst:
            valid = False
    if valid:
        result.append(lst)

If this is going to be true list comparisons (where search and listing are both lists of lists), you'll need to find a more robust solution.

Upvotes: 1

Related Questions