CODEWITHSUNDEEP
javascriptjavajqueryjsonservlets
Jsel
Jsel

Reputation: 199

not able to get JSON string in servlet

I am trying to pass some variables through JSON from JSP to servlet through ajax call. But i am getting null value at servlet side. Please some one help me on to find out where i am making mistake/ what i missed

//JSON	
		var masterdata = new Object();
	    masterdata.grn = $('#grn').val();
	    masterdata.pono = $('#pono').val();
	    masterdata.podt = $('#podt').val();
      
//call the servlet to insert the data only when error = 0
		if (error != 1){
			$.ajax({
				url : 'insertserv',
				type: 'POST',
				dataType: 'json',
		        data: {test : JSON.stringify(masterdata)},
		        contentType: 'application/json',
		        mimeType: 'application/json',
				success : function(data) {
							alert('Hi');
						}			
		          });
		    }
		else{
			alert("Save cannot be performed. Please check the entered data!");
		}
	  	});

public class insertserv extends HttpServlet {
	private static final long serialVersionUID = 1L;
	
	
	protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException 
	{
		System.out.println("I am inside insert");
		String masterdata = request.getParameter("test");
		System.out.println("masterdata :  "+masterdata);
		
		response.setContentType("text/plain");
	}
}

Upvotes: 3

Views: 847

Answers (2)

Ravi Pitroda
Ravi Pitroda

Reputation: 69

Replace your ajax code with my code...

//JSON	
		var masterdata = new Object();
	    masterdata.grn = $('#grn').val();
	    masterdata.pono = $('#pono').val();
	    masterdata.podt = $('#podt').val();
      
//call the servlet to insert the data only when error = 0
		if (error != 1){
			$.ajax({
				url : 'insertserv',
				type: 'POST',
				dataType: 'json',
		        data: JSON.stringify({"test" :masterdata}),
		        contentType: 'application/json',
		        mimeType: 'application/json',
				success : function(data) {
							alert('Hi');
						}			
		          });
		    }
		else{
			alert("Save cannot be performed. Please check the entered data!");
		}
	  	});

To get data in servlet 

 BufferedReader br = new BufferedReader(new InputStreamReader(request.getInputStream()));
      String json = "";

            if (br != null) {
                json = br.readLine();
            }
 JSONObject wholedata= new JSONObject(json);

now the object wholedata has a your json..

if you are using JSON.stringify() then you have to use BufferedReader in servlet , You can use request.getparameter in servlet when you are passing data in URL of servlet.

Upvotes: 2

Jai
Jai

Reputation: 74738

If your backend is responding with json content then only dataType:"json" works. Try change the response type: 

response.setContentType("application/json");

Because your ajax is expecting json from the backend with dataType:"json",.

or vice-versa.

change the dataType to text: dataType:"text", as the response header says response.setContentType("text/plain");. But in this case you have to use JSON.parse() to parse the json string. 

//JSON  
var masterdata = new Object();
masterdata.grn = $('#grn').val();
masterdata.pono = $('#pono').val();
masterdata.podt = $('#podt').val();

//call the servlet to insert the data only when error = 0
if (error != 1) {
  $.ajax({
    url: 'insertserv',
    type: 'POST',
    dataType: 'text', //<------change this
    data: {
      test: JSON.stringify(masterdata)
    },
    contentType: 'application/json',
    mimeType: 'application/json',
    success: function(data) {
      alert('Hi');
    }
  });
} else {
  alert("Save cannot be performed. Please check the entered data!");
}
});

Upvotes: 0

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