CODEWITHSUNDEEP
wpf.net-3.5
Russ
Russ

Reputation: 12540

Is there a DesignMode property in WPF?

In Winforms you can say 

if ( DesignMode )
{
  // Do something that only happens on Design mode
}

is there something like this in WPF?

Upvotes: 108

Views: 54126

Answers (6)

CodingNinja
CodingNinja

Reputation: 81

At design time, Application.Current is Microsoft.VisualStudio.XSurface.Wpf.WpfSurfaceApp, and at run time, Application.Current is your App.cs, so we can easily write the following code.

public static bool IsInDesignMode => Application.Current is not App;

Upvotes: 0

Manfred Radlwimmer
Manfred Radlwimmer

Reputation: 13394

Late answer, I know - but for anyone else who wants to use this in a DataTrigger, or anywhere in XAML in general:

xmlns:componentModel="clr-namespace:System.ComponentModel;assembly=PresentationFramework"

<Style.Triggers>
    <DataTrigger Binding="{Binding RelativeSource={RelativeSource Self}, 
                 Path=(componentModel:DesignerProperties.IsInDesignMode)}" 
                 Value="True">
        <Setter Property="Visibility" Value="Visible"/>
    </DataTrigger>
</Style.Triggers>

Upvotes: 11

Jeson Martajaya
Jeson Martajaya

Reputation: 7352

Use this one:

if (Windows.ApplicationModel.DesignMode.DesignModeEnabled)
{
    //design only code here
}

(Async and File operations wont work here)

Also, to instantiate a design-time object in XAML (d is the special designer namespace)

<Grid d:DataContext="{d:DesignInstance Type=local:MyViewModel, IsDesignTimeCreatable=True}">
...
</Grid>

Upvotes: -1

Enrico Campidoglio
Enrico Campidoglio

Reputation: 59963

Indeed there is:

System.ComponentModel.DesignerProperties.GetIsInDesignMode

Example:

using System.ComponentModel;
using System.Windows;
using System.Windows.Controls;

public class MyUserControl : UserControl
{
    public MyUserControl()
    {
        if (DesignerProperties.GetIsInDesignMode(this))
        {
            // Design-mode specific functionality
        }
    }
}

Upvotes: 163

serhio
serhio

Reputation: 28586

For any WPF Controls hosted in WinForms, DesignerProperties.GetIsInDesignMode(this) does not work.

So, I created a bug in Microsoft Connect and added a workaround:

public static bool IsInDesignMode()
{
    if ( System.Reflection.Assembly.GetExecutingAssembly().Location.Contains( "VisualStudio" ) )
    {
        return true;
    }
    return false;
}

Upvotes: 23

Massimiliano
Massimiliano

Reputation: 17000

In some cases I need to know, whether a call to my non-UI class is initiated by the designer (like if I create a DataContext class from XAML). Then the approach from this MSDN article is helpful:

// Check for design mode. 
if ((bool)(DesignerProperties.IsInDesignModeProperty.GetMetadata(typeof(DependencyObject)).DefaultValue)) 
{
    //in Design mode
}

Upvotes: 48

Related Questions