CODEWITHSUNDEEP
java
zuzu
zuzu

Reputation: 411

Remove spaces from a user input String

I'm trying to create a code to remove spaces in a user input String, but I receive an error at line 16.

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 15 at practice5.main(practice5.java:16)

Note: We are not allowed to use the replace method of Java. I need to code it manually.

Here's my code:

import java.util.Scanner;

public class practice5{
    public static void main(String args[]){
        Scanner scanner = new Scanner(System.in);
        String line;
        System.out.print("Sentence: ");
        line = scanner.nextLine();
        char phrase[] = line.toCharArray();
        int i = 0;
        int n = 0;

        while(phrase[i] != '\0') {
            if(phrase[i] == ' ') {
                for(n=i; n<phrase.length; n++) {
                    phrase[n] = phrase[n+1];
                }
            }
            i++;
        }

        String output = new String(phrase);
        System.out.print(output);
    }
}

Thank you!

Upvotes: 1

Views: 3983

Answers (6)

Naman
Naman

Reputation: 2203

Try using below code it may help

public static void main(String args[]) {

    Scanner scanner = new Scanner(System.in);
    String line;
    System.out.print("Sentence: ");
    line = scanner.nextLine();
    char phrase[] = line.toCharArray();
    String result = "";

    for (int i = 0; i < phrase.length; i++) {
        if (phrase[i] != ' ') {
            result += phrase[i];
        }           
    }

    System.out.println(result);
}

Upvotes: 1

MicD
MicD

Reputation: 196

Use CharMatcher to determine

whether a character is whitespace according to the latest Unicode standard

CharMatcher.whitespace().trimAndCollapseFrom("user input","");

Upvotes: 0

Shadab Faiz
Shadab Faiz

Reputation: 2508

Reason for error:ArrayIndexOutOfBound

suppose yor sentence is: abc.Now when you will execute your code...this is happening...

1st iteration: i is on the index 0(i.e at a).2nd iteration,i is on index 1 (i.e at b) and on 3rd iteration,i is on index 3 (on c),and again i is incremented by 1,so now i=4.Now 

while(phrase[i]!='\0')

will return such exception because you are comparing value at index 4 while is not available.Hence,such exception is occuring.

Upvotes: 1

adeen-s
adeen-s

Reputation: 156

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 15 at practice5.main(practice5.java:16)

The ArrayIndexOutOfBoundsException is thrown when a call to an array element is made at an index that does not exist.

In your code, at line 16, you are calling phrase[n+1] which works fine for all cases except when n==(phrase.length-1) because then n+1 will be equal to phrase.length.

Length is counted starting from 1 whereas indices are counted starting from 0. Therefore, during the last iteration, phrase[n+1] is equivalent to phrase[phrase.length] which is an out of bound index.

You can correct it by reducing the loop iterations by 1.

Upvotes: 1

Mureinik
Mureinik

Reputation: 312404

Why reinvent the wheel? Just use String's replace method:

String output = line.replace(" ", "");

Upvotes: 0

Markus
Markus

Reputation: 1171

You can use a function of the String class. Just use line.replace(" ","")

Upvotes: 1

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