CODEWITHSUNDEEP
python-2.7
Tine
Tine

Reputation: 35

Counting vowels followed by consonants

I want to count the vowels in a text, this I can do. But I also want to count the amount of vowels followed by a consonant and the amount of vowels followed by a vowel. Can somebody help me with this?

This is what I have so far but it says invalid syntax for the line where I use i+1 in vowels.

s = "text"
vowels = set("aeuio")
consonants = set("qwrtypsdfghjklzxcvbnm")

vowelcount=0
vowelvowelcount=0
consonantcount=0
consvowelcount=0
consconscount=0
vowelconscount=0

for i in s:
    if i in vowels:
        vowelcount += 1
    if i in consonants:
        consonantcount +=1

for i in s:
    if (i in vowels,and i+1 in vowels):
        vowelvowelcount +=1

print ("number of vowels:",  vowelcount)
print ("number of consonants:", consonantcount)
print ("number of vowels followed by vowels:", vowelvowelcount)

Upvotes: 1

Views: 117

Answers (2)

sangheestyle
sangheestyle

Reputation: 1077

I like Willem's answer. I have another option. I might want to use enumerate in this case.

for i, char in enumerate(s[:-1]):
    if char in vowels and s[i+1] in vowels:
        vowelvowelcount +=1

Upvotes: 1

willeM_ Van Onsem
willeM_ Van Onsem

Reputation: 477160

If you use for i in s, i is not an index: it is a character. A quick way to solve this is using:

for i in range(len(s)-1):
    if s[i] in vowels and s[i+1] in consonants:
        vowelconscount += 1
    elif s[i] in vowels and s[i+1] in vowels:
        vowelvowelcount += 1
    # ...

Here we use range(..) to iterate over all indices up to (but excluding) len(s)-1. For each of these indices i we check if the character in s at position i (that is s[i]) is vowels and the next character s[i+1] is a cononant.

Upvotes: 1

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