CODEWITHSUNDEEP
cdoubleformat-specifiersconversion-specifier
Ambitions
Ambitions

Reputation: 2581

I have written a code to convert from Celisius to Fahrenheit but the output is too huge

The code is:

#include <stdio.h>
#include <stdlib.h>

int main() {
    double C, F;
    printf("Enter the temperature in Celisius: ");
    scanf("%f", &C);
    F = 32 + (C * (180.0 / 100.0));
    printf("%f C = %f F\n", C, F);
    system("pause");
    return 0;
}

The output is:

Enter the temperature in Celisius: 100
-92559604910177974000000000000000000000000000000000000000000000.000000 C = -166607288838320360000000000000000000000000000000000000000000000.000000 F

Upvotes: 1

Views: 76

Answers (1)

Sourav Ghosh
Sourav Ghosh

Reputation: 134346

You got wrong conversion specifier there with double for scanf(). You need to use

  scanf("%lf", &C);

To add the relevant quote, from C11, chapter §7.21.6.2

l (ell)

Specifies that a following d, i, o, u, x, X, or n conversion specifier applies to an argument with type pointer to long int or unsigned long int; that a following a, A, e, E, f, F, g, or G conversion specifier applies to an argument with type pointer to double; or that a following c, s, or [ conversion specifier applies to an argument with type pointer to wchar_t.

That said, you must check the return value of scanf() to ensure the success of the call. Otherwise, you'll end up using the value of an uninitialized variable.

Upvotes: 4

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