CODEWITHSUNDEEP
c#.netrandom
Fernando Sousaa
Fernando Sousaa

Reputation: 65

Generate random number - Higher value

I have this:

int minValue = int.Parse(min.Text);
int maxValue = int.Parse(max.Text);
Random rnd = new Random();
int final = rnd.Next(minValue, maxValue);
result.Text = final.ToString("");

I'm going to get the two values (lower value and higher value) to two textboxes. These values are entered by the user. When I generate the random number, in no situation does the higher value appear. For example, the user enters 1 and 5. I repeatedly generate a number and in no situation does the number 5 appear. It only appears either 1, or 2, or 3, or 4, not 5. Why?

Upvotes: 0

Views: 207

Answers (3)

RahDeshpande
RahDeshpande

Reputation: 23

int minValue = int.Parse(min.Text);
int maxValue = int.Parse(max.Text)+1;
Random rnd = new Random();
int final = rnd.Next(minValue, maxValue);
result.Text = final.ToString("");

This will work because when it takes maxvalue range starts from minValue to maxValue-1.

Upvotes: 1

Mithilesh Gupta
Mithilesh Gupta

Reputation: 2930

If you look at function docs: https://msdn.microsoft.com/en-us/library/2dx6wyd4(v=vs.110).aspx

The higher value is exclusive.

To include it you need to do :

int final = rnd.Next(minValue, maxValue+1);

Upvotes: 6

Maksim Simkin
Maksim Simkin

Reputation: 9679

Because Random.Next gives random value exclusive upper bound.

https://msdn.microsoft.com/library/2dx6wyd4(v=vs.110).aspx

Upvotes: 8

Related Questions