Reputation: 391
I have a data frame like as follows:
Col1 Col2 Col3
A B C
D E F
G H I
I am trying to keep lines matching 'B' in 'Col2' OR F in 'Col3', in order to get:
Col1 Col2 Col3
A B C
D E F
I tried:
data[(grep("B",data$Col2) || grep("F",data$Col3)), ]
but it returns the entire data frame.
NOTE: it works when calling the 2 grep one at a time.
Upvotes: 2
Views: 18247
Reputation: 887911
Or using a single grepl
after paste
ing the columns
df1[with(df1, grepl("B|F", paste(Col2, Col3))),]
# Col1 Col2 Col3
#1 A B C
#2 D E F
Upvotes: 6
Reputation: 204
The data.table package makes this type of operation trivial due to its compact and readable syntax. Here is how you would perform the above using data.table:
> df1 <- structure(list(Col1 = c("A", "D", "G"), Col2 = c("B", "E", "H"
+ ), Col3 = c("C", "F", "I")), .Names = c("Col1", "Col2", "Col3"
+ ), row.names = c(NA, -3L), class = "data.frame")
> library(data.table)
> DT <- data.table(df1)
> DT
Col1 Col2 Col3
1: A B C
2: D E F
3: G H I
> DT[Col2 == 'B' | Col3 == 'F']
Col1 Col2 Col3
1: A B C
2: D E F
>
data.table performs its matching operations with with=TRUE by default. Note that the matching is much faster if you set keys on the data but that is for another topic.
Upvotes: 0
Reputation: 12723
with(df1, df1[ Col2 == 'B' | Col3 == 'F',])
# Col1 Col2 Col3
# 1 A B C
# 2 D E F
Using grepl
with(df1, df1[ grepl( 'B', Col2) | grepl( 'F', Col3), ])
# Col1 Col2 Col3
# 1 A B C
# 2 D E F
Data:
df1 <- structure(list(Col1 = c("A", "D", "G"), Col2 = c("B", "E", "H"
), Col3 = c("C", "F", "I")), .Names = c("Col1", "Col2", "Col3"
), row.names = c(NA, -3L), class = "data.frame")
Upvotes: 4