Reputation: 2056
I've generated a Spring Boot web application using Spring Initializer, embedded Tomcat, Thymeleaf template engine, and package as an executable JAR file.
Technologies used:
Spring Boot 1.4.2.RELEASE, Spring 4.3.4.RELEASE, Thymeleaf 2.1.5.RELEASE, Tomcat Embed 8.5.6, Maven 3, Java 8
This is my security config class:
@Configuration
@EnableWebSecurity
@PropertySource("classpath:/config/app-${APP-KEY}.properties")
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Value("${securityConfig.formLogin.loginPage}")
private String loginPage;
@Bean
public StandardPasswordEncoder encoder() {
return new StandardPasswordEncoder();
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http
.formLogin()
.loginPage(loginPage)
.permitAll()
.loginProcessingUrl("/tdk/login")
.failureUrl("/tdk/login?error=true")
.defaultSuccessUrl("/events/list")
.and()
.exceptionHandling()
.accessDeniedPage("/denied")
.and()
.authorizeRequests()
.antMatchers("/resources/**").permitAll()
.antMatchers("/mockup/**").permitAll()
.antMatchers("/users/**").permitAll()
.antMatchers("/books/**").permitAll()
.antMatchers("/welcome/**").authenticated()
.and()
.logout()
.permitAll()
.logoutSuccessUrl("/index.html");
}
@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
auth
.inMemoryAuthentication()
.passwordEncoder(new StandardPasswordEncoder())
.withUser("test1").password("c1f02fa50809b7f715576198eda6466cd17f63404ae6eded7c22290b025baf3868bc8f785267d4ae").roles("ADMIN").and()
.withUser("test2").password("test2").roles("USER").and()
.withUser("test3").password("test3").roles("SUPERADMIN");
}
@Bean
public static PropertySourcesPlaceholderConfigurer propertyDefaultConfig() {
return new PropertySourcesPlaceholderConfigurer();
}
}
This is my Junit Tests that works properly
public class StandardPasswordEncoderTests {
@Test
public void getPasswordForTest1() {
StandardPasswordEncoder encoder = new StandardPasswordEncoder();
String password = "test1";
assertTrue(
encoder.matches(password, "c1f02fa50809b7f715576198eda6466cd17f63404ae6eded7c22290b025baf3868bc8f785267d4ae"));
}
}
Here my login template
<form th:action="@{/tdk/login}" method="post">
<p th:if="${param.error}">
Bad Credentials ${param.error}
</p>
<p th:if="${loginError}" class="error">Wrong user or password</p>
<div class="input_label"><i class="fa fa-user"></i><input type="text" name="user" placeholder="User" /></div>
<div class="input_label"><i class="fa fa-key"></i><input type="password" name="pass" placeholder="Password" /></div>
<input type="submit" value="LOGIN" />
</form>
But whatever I put:
test1 / c1f02fa50809b7f715576198eda6466cd17f63404ae6eded7c22290b025baf3868bc8f785267d4ae
or
test2 / test2
I see the message Bad Credentials ${param.error}
in the output of my template
Upvotes: 1
Views: 807
Reputation: 16969
The parameter names for username and password in your login page are not matching the names in Spring Security configuration.
You could change the Spring Security configuration to use the parameter names from your login page. Or you could change the login page to use the default parameter names.
See FormLoginConfigurer#usernameParameter
:
The HTTP parameter to look for the username when performing authentication. Default is "username".
and FormLoginConfigurer#passwordParameter
:
The HTTP parameter to look for the password when performing authentication. Default is "password".
Your modified login page (with default parameter names):
<form th:action="@{/tdk/login}" method="post">
<p th:if="${param.error}">
Bad Credentials ${param.error}
</p>
<p th:if="${loginError}" class="error">Wrong user or password</p>
<div class="input_label">
<i class="fa fa-user"></i>
<input type="text" name="username" placeholder="User" />
</div>
<div class="input_label">
<i class="fa fa-key"></i>
<input type="password" name="password" placeholder="Password" />
</div>
<input type="submit" value="LOGIN" />
</form>
Upvotes: 1