CODEWITHSUNDEEP
pythonstringlist
bmikolaj
bmikolaj

Reputation: 486

Generating a list of substrings not in a list of strings

I have a list of strings and a list of substrings. I want to generate a list of substrings not in the list of strings.

substring_list=["100", "101", "102", "104", "105"]
string_list=["101 foo", "102 bar", "103 baz", "104 lorem"]

I tried to do new_list = [s for s in substring_list if s not in [i for i in string_list]], but this doesn't work. I've also tried various uses of any() but have had no luck.

I'd like to return new_list=["100", "105"].

Upvotes: 1

Views: 128

Answers (3)

Eric Duminil
Eric Duminil

Reputation: 54223

Coming from a Ruby background and since Python has any and all, I looked for a none function or method but was surprised to see it doesn't exist.

If you often use not any or all not, it could be interesting to define none() :

def none(iterable):
    for element in iterable:
        if element:
            return False
    return True

substring_list = ["100", "101", "102", "104", "105"]
string_list = ["101 foo", "102 bar", "103 baz", "104 lorem"]

print([sub for sub in substring_list if none(sub in s for s in string_list)])
# ['100', '105']

It might lead to confusion with None though. That's probably the reason why it doesn't exist.

Upvotes: 1

akuiper
akuiper

Reputation: 214957

You can try this:

[sub for sub in substring_list if all(sub not in s for s in string_list)]
# ['100', '105']

Or alternatively:

[sub for sub in substring_list if not any(sub in s for s in string_list)]
# ['100', '105']

Upvotes: 5

shimon
shimon

Reputation: 1

Code written returns all because "for i in string_list" creates a new set identical string_list array solve it is split handy split the organs to benefit string_list and then when you start i [0] you create similar string_list system but contains only numbers without letters

so

new_list = [s for s in substring_list if s not in [i.split()[0] for i in string_list]]

Upvotes: -1

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