Reputation: 5690
Having a variadic template is simple, and I can specialize it so it will only accept a TStringConstant
that is a string_constant
of some char
s:
template <typename TStringConstant, typename TValue>
class entry;
template <char... key, typename TValue>
class entry<string_constant<key...>, TValue>{}
If I wanted to make a template class that would accept a variadic number of TStringConstant
s of different char
s, would there be a way to do it? Perhaps with template template parameters?
So that all of the following would be valid:
entry_list<string_constant<'c','b','a'>, string_constant<'d','e','f','g'>>();
entry_list<string_constant<'c','b','a'>, string_constant<'d','e','f','g'>, string_constant<'d','e','z','z'>>();
entry_list<string_constant<'a','b','c'>>();
Bonus if it will reject entry_list<something_else<'c','b','a'>>
just like entry<something_else<'c','b','a'>, bool>
will be fail to compile.
Upvotes: 4
Views: 274
Reputation: 66230
The real problem I see is: how do you want to use the variadic lists of chars of your entry_list
class?
I like the bolov's solution (+1) but, if you accept a recursive solution, I propose the use of inheritance.
The following is a full example
template <char ...>
struct string_constant
{ };
template <char ...>
struct something_else
{ };
template <typename ...>
class entry_list;
template <>
class entry_list<>
{ };
template <char ... keys, typename ... Scs>
class entry_list<string_constant<keys ...>, Scs ...>
: public entry_list<Scs ...>
{ };
int main ()
{
entry_list<string_constant<'c','b','a'>,
string_constant<'d','e','f','g'>>(); // compile
entry_list<string_constant<'c','b','a'>,
string_constant<'d','e','f','g'>,
string_constant<'d','e','z','z'>>(); // compile
entry_list<string_constant<'a','b','c'>>(); // compile
//entry_list<something_else<'c','b','a'>>(); // compilation error
//entry_list<string_constant<'c','b','a'>, bool>(); // compilation error
}
If you don't want use inheritance, you can use static_assert()
instead as follows
template <char ... keys, typename ... Scs>
class entry_list<string_constant<keys ...>, Scs ...>
{ static_assert(sizeof(entry_list<Scs...>), "!"); };
Upvotes: 0
Reputation: 75874
You can do it with a static_assert
. I don't know how to implement it in a sfinae friendly way, but I guess you don't care about that.
So here it goes:
template <class... Args> struct entry {
static_assert(are_string_constant<Args...>::value, "invalid template args for entry");
};
auto test()
{
entry<string_constant<'c', 'd'>> e1; // OK
entry<string_constant<'c', 'd'>, string_constant<'a', 'b', 'c', 'd'>> e2; // OK
// entry<int,
// string_constant<'c', 'd'>,
// string_constant<'a', 'b', 'c', 'd'>> e3; // static_assert kicks in
// entry<definitely_not_string_constant<'c', 'd'>,
// string_constant<'a', 'b', 'c', 'd'>> e4; // static_assert kicks in
}
The building of are_string_constant
is pretty straight forward:
template <char... Args> struct string_constant {};
template <char... Args> struct definitely_not_string_constant {};
// --- is_string_constant -----
template <class T> struct is_string_constant : std::false_type {};
template <char... Args>
struct is_string_constant<string_constant<Args...>> : std::true_type {};
// --- are_string_constant -----
template <class... Args> struct are_string_constant;
template <class A0, class... Args>
struct are_string_constant<A0, Args...>
: std::integral_constant<bool, (is_string_constant<A0>::value &&
are_string_constant<Args...>::value)>::type
{};
template <class T> struct are_string_constant<T> : is_string_constant<T>::type {};
In c++17 the implementation is easier with fold expressions (because you don't need the are_string_constant
):
template <class... Args>
struct entry {
static_assert((... && is_string_constant<Args>::value),
"invalid template args for entry");
};
Upvotes: 3