CODEWITHSUNDEEP
javascript
OpenTheCSV
OpenTheCSV

Reputation: 93

Why do these two if statements have different meanings?

Let's take the code

 var dumb = [1,2,3,4,5,6]

 for (var x = 0; x < dumb.length; x++){
    if (dumb[x] % 2) {
       console.log(dumb[x]);
    }
}

In the above program, it produces (1,3,5) But if the if statement was: (if dumb[x] % 2 === 0), it produces (2,4,6)

Why Does

    if (dumb[x] % 2)

and 

    if (dumb[x] % 2 === 0)

produce difference results?

Upvotes: 1

Views: 45

Answers (2)

TankorSmash
TankorSmash

Reputation: 12777

You're comparing the output of the modulo operator, vs the output of a boolean expression.

dumb[x] % 2

works out to a number, while

dumb[x] % 2 === 0

works out to a boolean, true or false.

If the first expression works out to 0, it'll be falsey, otherwise it'll be truthy.

Upvotes: 1

kemiller2002
kemiller2002

Reputation: 115538

In a conditional statement in JavaScript 0 is false and all other numbers are true. 

if (dumb[x] % 2) // if the numbers is even, it's false because the remainder is 0.

and

if (dumb[x] % 2 === 0) 
//if even it's true, because the remainder 0 which is what you are comparing it to.

Upvotes: 2

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